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2 years ago

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1 answer:

Ksju [112]2 years ago

4 0

The true statements are:

The interquartile range is 10.

The data is skewed.

<h3>What are the true statements?</h3>

A box plot is used to study the distribution and level of a set of scores

The end of the first whisker represents the minimum number and the end of the second whisker represents the maximum number.

On the box, the first line to the left represents the lower (first) quartile. The next line on the box represents the median. The third line on the box represents the upper (third) quartile. The interquartile range is the difference between the first and third quartile.

Interquartile range = 9 - (-1) = 10

A box plot is negative skewed because the median is not at the center of the box.

An outlier would be within: (Q1 - 1.5 * IQR or Q3 + 1.5 * IQR).

- 1 - (1.5 x 10 ) = -16

9 + (1.5 x 10) = 24

To learn more about box plots, please check: brainly.com/question/27215146

#SPJ1

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3 years ago

The thickness of a flange on an aircraft component is uniformly distributed between 0.95 and 1.05 millimeters. (a) Determine the

maxonik [38]

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b) A thickness of 0.96 millimeters is exceeded by 90% of the flanges

Step-by-step explanation:

A distribution is called uniform if each outcome has the same probability of happening.

The uniform distributon has two bounds, a and b, and the probability of finding a value higher than x is given by:

$P(X > x) = \frac{b - x}{b - a}$

The thickness of a flange on an aircraft component is uniformly distributed between 0.95 and 1.05 millimeters.

This means that $a = 0.95, b = 1.05$

(a) Determine the proportion of flanges that exceeds 1.00 millimeters.

$P(X > 1) = \frac{1.05 - 1}{1.05 - 0.95} = \frac{0.05}{0.1} = 0.5$

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(b) What thickness is exceeded by 90% of the flanges?

This is x for which:

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3 years ago