Answer:
0.264 mm
Step-by-step explanation:
Number of sheets = 1000
Thickness of entire sheet = 264 mm
The thickness of the sheet is :
Thickness of entire sheet / number of sheets
264 mm / 1000
= 0.264 mm
Answer:
Simple
Step-by-step explanation:
Remove cables from battery terminals. ...
Remove the screws or fasteners holding the battery in place; then Remove the Battery. ...
Inspect the tray the old battery was resting on. ...
Position your new car battery on the tray. ...
Replace the screws/fasteners to the new battery to secure it in place.
Step 6. Reconnect your battery cables in the reverse order in which you took them off
Answer:Set up the polynomials to be divided. If there is not a term for every exponent, insert one with a value of
0
.
x
+
1
4
x
2
-
2
x
-
5
Divide the highest order term in the dividend
4
x
2
by the highest order term in divisor
x
.
4
x
x
+
1
4
x
2
-
2
x
-
5
Multiply the new quotient term by the divisor.
4
x
x
+
1
4
x
2
-
2
x
-
5
+
4
x
2
+
4
x
The expression needs to be subtracted from the dividend, so change all the signs in
4
x
2
+
4
x
4
x
x
+
1
4
x
2
-
2
x
-
5
-
4
x
2
-
4
x
After changing the signs, add the last dividend from the multiplied polynomial to find the new dividend.
4
x
x
+
1
4
x
2
-
2
x
-
5
-
4
x
2
-
4
x
-
6
x
Pull the next terms from the original dividend down into the current dividend.
4
x
x
+
1
4
x
2
-
2
x
-
5
-
4
x
2
-
4
x
-
6
x
-
5
Divide the highest order term in the dividend
−
6
x
by the highest order term in divisor
x
.
4
x
-
6
x
+
1
4
x
2
-
2
x
-
5
-
4
x
2
-
4
x
-
6
x
-
5
Multiply the new quotient term by the divisor.
4
x
-
6
x
+
1
4
x
2
-
2
x
-
5
-
4
x
2
-
4
x
-
6
x
-
5
-
6
x
-
6
The expression needs to be subtracted from the dividend, so change all the signs in
−
6
x
−
6
4
x
-
6
x
+
1
4
x
2
-
2
x
-
5
-
4
x
2
-
4
x
-
6
x
-
5
+
6
x
+
6
After changing the signs, add the last dividend from the multiplied polynomial to find the new dividend.
4
x
-
6
x
+
1
4
x
2
-
2
x
-
5
-
4
x
2
-
4
x
-
6
x
-
5
+
6
x
+
6
+
1
The final answer is the quotient plus the remainder over the divisor.
4
x
−
6
+
1
x
+
1
Step-by-step explanation:
Answer:
ratio of a is 44:56, ratio of b is 97:3
fraction of a is 44/100, fraction of b is 97/100
decimal of a is 0.44, decimal of b is 0.97
percent of a is 97%, and percent of b is 97%
if this is wrong im so sorry :()()()()(
step-by-step explanation:
Step-by-step explanation:
<em>ap</em><em>p</em><em>ly </em><em>angle</em><em> </em><em>sum </em><em>property</em><em> </em><em>of </em><em>triangle</em><em> </em><em>in </em><em>the </em><em>given</em><em> </em><em>traingle </em><em>(</em><em> </em><em>instead</em><em> </em><em>of </em><em>this </em><em>u </em><em>can </em><em>write</em><em> </em><em>sum </em><em>of </em><em>all </em><em>the </em><em>interior</em><em> </em><em>angles </em><em>of </em><em>triangle</em><em> </em><em>is </em><em>1</em><em>8</em><em>0</em><em>°</em><em>)</em>
<em>so,</em>
<em>→</em><em> </em><em>8</em><em>0</em><em>°</em><em> </em><em>+</em><em> </em><em>5</em><em>0</em><em>°</em><em> </em><em>+</em><em> </em><em>x </em><em>=</em><em> </em><em>1</em><em>8</em><em>0</em><em>°</em>
<em>→</em><em> </em><em>1</em><em>3</em><em>0</em><em>°</em><em> </em><em>+</em><em> </em><em>x </em><em>=</em><em> </em><em>1</em><em>8</em><em>0</em><em>°</em>
<em>→</em><em> </em><em>x </em><em>=</em><em> </em><em>1</em><em>8</em><em>0</em><em>°</em><em> </em><em>-</em><em> </em><em>1</em><em>3</em><em>0</em><em>°</em>
<em>→</em><em> </em><em>x </em><em>=</em><em> </em><em>5</em><em>0</em><em>°</em>
<em>therefore</em><em>,</em><em> </em><em>value</em><em> </em><em>of </em><em>x </em><em>is </em><em>5</em><em>0</em><em>°</em><em>.</em>
<em><u>hope </u></em><em><u>this</u></em><em><u> answer</u></em><em><u> helps</u></em><em><u> you</u></em><em><u> </u></em><em><u>dear.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>take </u></em><em><u>care</u></em><em><u> </u></em><em><u>and </u></em><em><u>may </u></em><em><u>u</u></em><em><u> have</u></em><em><u> a</u></em><em><u> great</u></em><em><u> day</u></em><em><u> ahead</u></em><em><u>!</u></em><em><u>.</u></em>