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DochEvi [55]
2 years ago
9

Can someone please help me with this

Mathematics
1 answer:
kramer2 years ago
5 0

Answer:

y = 4x

y = -1/3 × x + 6

y = x + 1

y = 1

y = 5x

Step-by-step explanation:

the slope of a line is the factor of x in the equation representing the ratio of y/x. it stands for the number of units y changes, when x changes by another number of units.

like the factor 4 tells us that when x changes by 1, then y changes by 4.

a line parallel to another line means their slopes are identical (otherwise they could not be parallel).

the slope of a perpendicular line (cutting the other line in a 90 degree angle) is simply reversing y and x in the slope ratio. so, a slope of 4 (4/1) would simply turn into 1/4.

now the 5 tasks are easy, right ?

A y=4x-1, B y=4x + c

and because B passes through the origin = (0,0),

c is 0 (0=4×0 + c = c)

B y = 4x

A y=-3x+1, B y=-1/3 × x + c

and B passes through (12,2), 2 = -1/3 × 12 + c = -4 + c,

c = 2 + 4 = 6

B y = -1/3 × x + 6

A y = ax + c for (5,6) and (7,8), B is identical

6 = a×5 + c => c = 6 - a×5

8 = a×7 + c => 8 = a×7 + 6 - a×5 = a×2 + 6

=> a×2 = 8-6 = 2

=> a = 1, c = 6 - 1×5 = 1

=> A and B y = x + 1

A is vertical. B is perpendicular to it. perpendicular to vertical is horizontal. so, B is a flat line. which means y is a constant value (the same value for whatever value of x you want to use). so it goes flat in parallel to the x-axis through what value of y ? the point (4,1) tells us that y=1

and that is the equation for B

A 15x -3y = -6 => 3y = 15x + 6 => y = 5x + 2

B is parallel, so y = 5x + c

and B passes through (4,20), 20 = 5 × 4 + c = 20 + c,

c = 20 - 20 = 0

B y = 5x

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You are creating an open top box with a piece of cardboard that is 16 x 30“. What size of square should be cut out of each corne
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Answer:

\frac{10}{3} \ inches of square should be cut out of each corner to create a box with the largest volume.

Step-by-step explanation:

Given: Dimension of cardboard= 16 x 30“.

As per the dimension given, we know Lenght is 30 inches and width is 16 inches. Also the cardboard has 4 corners which should be cut out.

Lets assume the cut out size of each corner be "x".

∴ Size of cardboard after 4 corner will be cut out is:

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Now, finding the volume of box after 4 corner been cut out.

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Volume(v)= (30-2x)\times (16-2x)\times x

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\frac{d (4x^{3} -92x^{2} +480x)}{dx} = \frac{dv}{dx}

Differentiating the value

⇒\frac{dv}{dx} = 12x^{2} -184x+480

taking out 12 as common in the equation and subtituting the value.

⇒ 0= 12(x^{2} -\frac{46x}{3} +40)

solving quadratic equation inside the parenthesis.

⇒12(x^{2} -12x-\frac{10x}{x} +40)=0

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⇒[x(x-12)-\frac{10}{3} (x-12)]= 0

We can again take common as (x-12).

⇒ x(x-12)[x-\frac{10}{3} ]=0

∴(x-\frac{10}{3} ) (x-12)= 0

We have two value for x, which is 12 and \frac{10}{3}

12 is invalid as, w= (16-2x)= 16-2\times 12

∴ 24 inches can not be cut out of 16 inches width.

Hence, the cut out size from cardboard is \frac{10}{3}\ inches

Now, subtituting the value of x to find volume of the box.

Volume(v)= (30-2x)\times (16-2x)\times x

⇒ Volume(v)= (30-2\times \frac{10}{3} )\times (16-2\times \frac{10}{3})\times \frac{10}{3}

⇒ Volume(v)= (30-\frac{20}{3} ) (16-\frac{20}{3}) (\frac{10}{3} )

∴  Volume(v)= 725.93 inches³

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