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2 years ago

Anybody can help me im stuck U_U

Mathematics

1 answer:

Naddik [55]2 years ago

7 0

Graph (b) represents the data provided that option (b) would be the correct choice.

A mathematical notion called the line of the best fit connects points spread throughout a graph. It's a type of linear regression that uses scatter data to figure out the best way to define the dots' relationship.

$\rm m = \dfrac{n\sum xy-\sum x \sum y}{n\sum x^2 - (\sum x)^2}\\\\\\\rm c = \dfrac{\sum y -m \sum x}{n}$

We have the data shown in the table.

The equation of the line M = 3n represents the data provided,

After plotting all the points on the coordinate plane.

We will get a graph that represents the data.

Thus, graph (b) represents the data provided the option (b) would be the correct choice.

Learn more about the line of best fit here:

brainly.com/question/14279419

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The manager went over the sales of mobile phones at the store and found that the mean sale was 45, with a standard deviation of

d1i1m1o1n [39]

The z-score of the sale of mobile phones on that day is 1.75

Step-by-step explanation:

The formula of z-score is z = (x - μ)/σ, where:

x is the score
μ is the mean
σ is the standard deviation

∵ The mean sale was 45

∴ μ = 45

∵ The standard deviation was 4

∴ σ = 4

∵ 52 mobile phones were sold on a particular day

∴ x = 52

To find z-score of the sale of mobile phones on that day substitute the values of x, μ, and σ in the formula of z-score

∵ $z=\frac{52-45}{4}$

∴ $z=\frac{7}{4}$

∴ z = 1.75

The z-score of the sale of mobile phones on that day is 1.75

Learn more:

You can learn more about z-score in brainly.com/question/7207785

#LearnwithBrainly

3 0

4 years ago

Ashley began a new fitness and wellness program. After 30 days she weighed 124 pounds.

Pie

Ashley lost approximately 0.53 pounds per day. After 30 days, she lost 16 pounds and 16/30=0.53

8 0

3 years ago

X and y are normal random variables with e(x) = 2, v(x) = 5, e(y) = 6, v(y) = 8 and cov(x,y)=2. determine the following: e(3x 2y

andriy [413]

The result for the given normal random variables are as follows;

a. E(3X + 2Y) = 18

b. V(3X + 2Y) = 77

c. P(3X + 2Y < 18) = 0.5

d. P(3X + 2Y < 28) = 0.8729

<h3>What is normal random variables?</h3>

Any normally distributed random variable having mean = 0 and standard deviation = 1 is referred to as a standard normal random variable. The letter Z will always be used to represent it.

Now, according to the question;

The given normal random variables are;

E(X) = 2, V(X) = 5, E(Y) = 6, and V(Y) = 8.

Part a.

Consider E(3X + 2Y)

$\begin{aligned}E(3 X+2 Y) &=3 E(X)+2 E(Y) \\&=(3) (2)+(2)(6 )\\&=18\end{aligned}$