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jeyben [28]
2 years ago
9

Anybody can help me im stuck U_U

Mathematics
1 answer:
Naddik [55]2 years ago
7 0

Graph (b) represents the data provided that option (b) would be the correct choice.

<h3>What is the line of best fit?</h3>

A mathematical notion called the line of the best fit connects points spread throughout a graph. It's a type of linear regression that uses scatter data to figure out the best way to define the dots' relationship.

\rm m = \dfrac{n\sum xy-\sum x \sum y}{n\sum x^2 - (\sum x)^2}\\\\\\\rm c = \dfrac{\sum y -m \sum x}{n}

We have the data shown in the table.

The equation of the line M = 3n represents the data provided,

After plotting all the points on the coordinate plane.

We will get a graph that represents the data.

Thus, graph (b) represents the data provided the option (b) would be the correct choice.

Learn more about the line of best fit here:

brainly.com/question/14279419

#SPJ1

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Brilliant_brown [7]
For this case we have a function of the form:
 y = A * (b) ^ t
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3 years ago
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A right-angled triangle has shorter side lengths exactly c^2-b^2 and 2bc units respectively, where b and c are positive real num
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Answer: hypotenuse = c^{2} + b^{2}

Step-by-step explanation: Pythagorean theorem states that square of hypotenuse (h) equals the sum of squares of each side (s_{1},s_{2}) of the right triangle, .i.e.:

h^{2} = s_{1}^{2} + s_{2}^{2}

In this question:

s_{1} = c^{2}-b^{2}

s_{2} = 2bc

Substituing and taking square root to find hypotenuse:

h=\sqrt{(c^{2}-b^{2})^{2}+(2bc)^{2}}

Calculating:

h=\sqrt{c^{4}+b^{4}-2b^{2}c^{2}+(4b^{2}c^{2})}

h=\sqrt{c^{4}+b^{4}+2b^{2}c^{2}}

c^{4}+b^{4}+2b^{2}c^{2} = (c^{2}+b^{2})^{2}, then:

h=\sqrt{(c^{2}+b^{2})^{2}}

h=(c^{2}+b^{2})

Hypotenuse for the right-angled triangle is h=(c^{2}+b^{2}) units

3 0
3 years ago
1 Solve for the unknown variable:
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Answer:

Approximately 6.4

Step-by-step explanation:

We can use the pythagorean thereom here, that tells us (a^2)+(b^2)=c^2. C is the hypotenuse, the side opposite from the right angle, while a and b are the other sides. We can insert 5 and 4 as a and b, and solve for c

:(5^2)+(4^2)=c^2

:25+16=c^2

:41=c^2

:sqrt(41)=6.4=c              (We square rooted both sides. 6.4 is only rounded to the nearest hundredths place.) Hope this helps!

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