Hello,
<u>Solution for A:</u>
Force = 3.00N
Mass = 0.50 Kgs
Time = 1.50 Seconds
According to newton's second law of motion;
Force = Mass times Acceleration(a)
3.00 = 0.50 * a
a = 3.00/0.50 = 6.00 m/s^2
We know that acceleration = Velocity / time
So Velocity = time * acceleration = 1.50 * 6 = 9.00 m/s^2
<u>Solution for B:</u>
The net force = 4.00N - 3.00N = 1.00N to the left
Force = 1.00N
Mass = 0.50Kg
Time = 3.00 Seconds
Again; F = MA (Where F is force, M is mass and A is acceleration)
1.00N = 0.5 * A
A = 1/0.5 = 2 m/s^2
Velocity = Acceleration * Time = 2 * 3 = 6 m/s
Answer:
Kinetic energy of the system = 2547.41 Joules.
Explanation:
Given:
Disk:
Mass of the disk (m) = kg
Radius of the disk (r) = cm = m
Cylinder:
Mass of the annular cylinder (M) = kg
Inner radius of the cylinder = m
Outer radius of the cylinder = m
The angular speed of the system = rev/s
Angular speed in in terms of Rad/sec = rad/sec
Formula to be used:
Rotational Kinetic energy, =
So, before that we have to work with the moment of inertia (MOI) of the system.
⇒ MOI of the system = MOI of the disk + MOI of the cylinder
⇒ MOI (system) =
⇒ MOI (system) =
⇒ MOI (system) = kg.m^2
Now
The rotational Kinetic energy.
⇒
Plugging the values.
⇒
⇒ Joules
Then
The kinetic energy of the rotational system is 2547.41 J.
<span>They occur when the Earth, the Sun, and the Moon are in a line. </span>
A : 30 seconds
B: T = 2π Square root of√L/g,
C: how many back-and-forth swings there are in a second, measured in hertz. f = [√(4.9)]/6.28 = 2.21/6.28 = 0.353 Hz.