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Elena-2011 [213]
3 years ago
12

When does a spring tide take place

Physics
2 answers:
Advocard [28]3 years ago
8 0
During the full moon and the new moon
dimulka [17.4K]3 years ago
6 0
<span>They occur when the Earth, the Sun, and the Moon are in a line. </span>
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Excellent human jumpers can leap straight up to a
Shkiper50 [21]

The speed that the person needs to leave the ground will be 4.32m/s

From the question given,

Height = 95cm

Since the person leave the ground v = 0m/s

acceleration due to gravity g = 9.8m/s²

Using the equation of motion

v² = u² + 2as

a = -g (upward motion)

s = h (distance changes to height)

The equation will become:

0² = u² - 2gh

0² = u² - 2(9.8)(0.95)

u² = 18.62

u = √18.62

u = 4.32

Hence the speed that the person needs to leave the ground will be 4.32m/s

Learn more here: brainly.com/question/20352766

8 0
2 years ago
A tennis player practices against a wall, hitting a 0.1 kg ball towards the
pantera1 [17]

Answer: 80 Newton

Explanation:

Initial velocity of ball = +20 m/s.

Final velocity of ball = -20 m/s

Mass of ball = 0.1kg

Time taken = 0.05 seconds

Average force = (Change in momentum of moving ball / Time taken)

Since, change in momentum = Mass (final velocity - initial velocity)

Change in momentum =0.1 x (-20 - (+20))

= 0.1 x (-20-20)

= 0.1 x (-40)

= -4.0 kgm/s

Then, put -4.0 kgm/s in the equation of force when Average Force = (Change in momentum / Time taken)

= (-4.0kgm/s / 0.05 seconds)

= 80Newton (note that the negative sign does not reflect on the magnitude of force)

Thus, the average force exerted on the ball is 80N

3 0
3 years ago
Two students who live on planet X. They want to estimate the circumference. The two students synchronize their watches before on
dexar [7]

Answer:

72000 miles

Explanation:

If the distance between the students is 600 miles, and this implies in a 3 degree difference in the sun position, that means this 600 miles is related to 3 degrees of the circunference of the planet.

So, to find the whole circunference of the planet, that is, 360 degrees, we just need to use a rule of three:

3 degrees -> 600 miles

360 degrees -> x miles

3x = 600 * 360

x = 600 * 360 / 3 = 72000 miles

7 0
3 years ago
The force per meter between the two wires of a jumper cable being used to start a stalled car is 0.244 N/m. (a) What is the curr
MakcuM [25]

Answer: current I is 144amp(A)

Explanation: The force per lenght F/L, current l, and separation distance r are related by the formula

F/L = permeability of space* I²/2*pi*r

Permeability of free space is 1.257*EXP {-6} Henry/meter

F/L is 0.244 N/m, pi is 3.142,

r is 1.7cm which is equal to 0.017meter.

I is what we are looking for.

Now we have after substitution,

0.244

= 1.257*EXP {-6} * I²/(2*3.142*0.017)

After cross multiplying and making I² subject of formula we have,

0.0261/(1.257*EXP {-6}) = I²

I = √{20736.7} =144ampere(A)

That means in each of the jumper wire there is 144amp(A)

8 0
3 years ago
Suppose one night the radius of the earth doubled but its mass stayed the same. What would be an approximate new value for the f
Alex17521 [72]

Answer:

g' = g/4

Explanation:

  • The value of the free-fall acceleration at the surface of the earth, can be obtained applying Newton's 2nd law, assuming that the only force acting on an object at the surface of the earth, is the one produced by the mass of the Earth, i.e. gravity.
  • This force can be expressed according  the Newton's Universal Law of Gravitation , as follows:

       F_{g} = G*\frac{m_{x} *m_{E} }{r_{E}^{2} }  (1)

  • From Newton's 2nd Law, we have:
  • F = m* a (2)
  • Since the left sides in (1) and (2) are equal each other, both right sides must be equal each other also.
  • Simplifying the mass m, we can write the acceleration a in (2) as the acceleration due to gravity, g, as follows:

       g = G*\frac{m_{E} }{r_{E}^{2} }  (3)

  • Since G is an universal constant, and the mass mE remains constant, if we double the radius of  the Earth, the new value for the acceleration due to gravity (let's call it g'), is as follows:

        g' = G*\frac{m_{E} }{(2r_{E})^{2} } =G*\frac{m_{E} }{4*r_{E}^{2} }  = g*\frac{1}{4}  =\frac{g}{4} (4)

4 0
3 years ago
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