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solniwko [45]
3 years ago
9

Until 1883, every city and town in the United States kept its own local time. Today, travelers reset their watches only when the

time change equals 1.0 h. How far, on the average, must you travel in degrees of longitude until your watch must be reset by 9 hours? (Hint: Earth rotates 360° in about 24 h.)
Physics
1 answer:
inna [77]3 years ago
7 0

Answer:

135° (degrees)

Explanation:

The Earth rotates 360° in about 24 h

How many degrees in 1 hour

360^{\circ}=24\ h\\\Rightarrow 1\ h=\frac{360}{24}\\\Rightarrow 1\ h=15^{\circ}

So, in 1 hour the Earth rotates 15 degrees. This means that a person would have to reset their watch by 1 hour after travelling 15 degrees

In 9 hours

9\ h=9\times 15^{\circ}=135^{\circ}\\\Rightarrow 9\ h=135^{\circ}

So, a person would have to travel 135 degrees in order to reset their watch by 9 hours.

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3 years ago
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Answer:

The weight of the body in the new planet is 100 newtons.

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From Newton's Law of Gravitation we find that gravitational force is directly proportional to mass of the planet and inversely proportional to the square of its radius. From this fact we can build the following relationship:

\frac{F_{1}\cdot R_{1}^{2}}{M_{1}} = \frac{F_{2}\cdot R_{2}^{2}}{M_{2}} (1)

Where:

F_{1}, F_{2} - Gravitational force, measured in newtons.

M_{1}, M_{2} - Mass of planet, measured in kilograms.

R_{1}, R_{2} - Radius of the planet, measured in meters.

If we know that F_{1} = 800\,N, \frac{M_{2}}{M_{1}} = \frac{1}{2} and \frac{R_{2}}{R_{1}} = 2, then the expected gravitational force in the new planet is:

F_{2} = F_{1}\cdot \left(\frac{M_{2}}{M_{1}} \right)\cdot \left(\frac{R_{1}} {R_{2}}\right)^{2}

F_{2} = (800\,N)\cdot \left(\frac{1}{2} \right)\cdot \left(\frac{1}{2}\right)^{2}

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The weight of the body in the new planet is 100 newtons.

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3 years ago
Two diodes are in series. The first diode has a voltage of 0.75 V and the second has a voltage of 0.8 V. If the current through
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The current in the second diode is 400mA

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