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3 years ago

I'm doing a task which involves magic v's, a maths pattern which has the rule of having the same total on each side. For e.g.

Mathematics

1 answer:

iogann1982 [59]3 years ago

6 0

Answer:

--1-- (of set 23456)

2 4

5 3

--2-- (of set 23456)

2 3

5 4

--3-- (of set 23456)

2 5

6 3

--4-- (of set 23456)

2 3

6 5

--5-- (of set 23456)

3 5

4 2

--6-- (of set 23456)

3 2

4 5

--7-- (of set 23456)

3 6

5 2

--8-- (of set 23456)

3 2

5 6

--9-- (of set 23456)

3 5

6 4

--10-- (of set 23456)

3 4

6 5

--11-- (of set 23456)

4 5

3 2

--12-- (of set 23456)

4 2

3 5

--13-- (of set 23456)

4 6

5 3

--14-- (of set 23456)

4 3

5 6

--15-- (of set 23456)

5 4

2 3

--16-- (of set 23456)

5 3

2 4

--17-- (of set 23456)

5 6

3 2

--18-- (of set 23456)

5 2

3 6

--19-- (of set 23456)

5 6

4 3

--20-- (of set 23456)

5 3

4 6

--21-- (of set 23456)

6 5

2 3

--22-- (of set 23456)

6 3

2 5

--23-- (of set 23456)

6 5

3 4

--24-- (of set 23456)

6 4

3 5

--1-- (of set 34567)

3 5

6 4

--2-- (of set 34567)

3 4

6 5

--3-- (of set 34567)

3 6

7 4

--4-- (of set 34567)

3 4

7 6

--5-- (of set 34567)

4 6

5 3

--6-- (of set 34567)

4 3

5 6

--7-- (of set 34567)

4 7

6 3

--8-- (of set 34567)

4 3

6 7

--9-- (of set 34567)

4 6

7 5

--10-- (of set 34567)

4 5

7 6

--11-- (of set 34567)

5 6

4 3

--12-- (of set 34567)

5 3

4 6

--13-- (of set 34567)

5 7

6 4

--14-- (of set 34567)

5 4

6 7

--15-- (of set 34567)

6 5

3 4

--16-- (of set 34567)

6 4

3 5

--17-- (of set 34567)

6 7

4 3

--18-- (of set 34567)

6 3

4 7

--19-- (of set 34567)

6 7

5 4

--20-- (of set 34567)

6 4

5 7

--21-- (of set 34567)

7 6

3 4

--22-- (of set 34567)

7 4

3 6

--23-- (of set 34567)

7 6

4 5

--24-- (of set 34567)

7 5

4 6

Step-by-step explanation:

This javascript code is extremely brute-force, but it does the job:

function checkIfInSet(i, set) {

return i.toString().split('').sort().join('') === set;

}

function checkIfMagic(s) {

return (parseInt(s[0]) + parseInt(s[1]) == parseInt(s[3]) + parseInt(s[4]))

}

function printMagic(s) {

console.log(`${s[0]} ${s[4]}`);

console.log(` ${s[1]} ${s[3]}`);

console.log(` ${s[2]}\n`);

}

function checkSet(set) {

let counter = 1;

for(let i=1; i<99999; i++) {

if (checkIfInSet(i, set) && checkIfMagic(i.toString())) {

console.log(`--${counter++}-- (of set ${set})`);

printMagic(i.toString());

}

checkSet('23456');

checkSet('34567');

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In a recent year one United States dollars was equal to about 82 Japanese yen

suter [353]

$8,200
$82,000
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5 0

3 years ago

A recent estimate by a large distributor of gasoline claims that 60% of all cars stopping at their service stations chose unlead

Anton [14]

Answer:

We reject the null hypothesis and conclude that at least 2 proportions differ from the stated value.

Step-by-step explanation:

There are 3 types of gas listed in the question.

Thus;

n = 3

DF = n - 1

DF = 3 - 1

DF = 2

Let's state the hypotheses;

Null hypothesis; H0: P_regular = P_super unleaded = 20%; P_i leaded = 60%

Alternative hypothesis; Ha: At least 2 proportions differ from the stated value.

Observed values are;

Regular gas; O = 51

Unleaded gas; O = 261

Super Unleaded; O = 88

Total observed values = 51 + 261 + 88 = 400

We are told that super unleaded and regular were each selected 20% of the time and that unleaded gas was chosen 60% of the time.

Thus, expected values are;

Regular gas; E = 20% × 400 = 80

Unleaded gas; E = 60% × 400 = 240

Super Unleaded; E = 20% × 400 = 80

Formula for chi Square goodness of fit is;

X² = Σ[(O - E)²/E]

X² = (51 - 80)²/80) + (261 - 240)²/240) + (88 - 80)²/80)

X² = 13.15

From the chi Square distribution table attached and using; DF = 2 and X² = 13.15, we can trace the p-value to be approximately 0.001

Also from online p-value from chi Square calculator attached, we have p to be approximately 0.001 which is similar to what we got from the table.

Now, if we take the significance level to be 0.05, it means the p-value is less than it and thus we reject the null hypothesis and conclude that at least 2 proportions differ from the stated value.

4 0

3 years ago

A program exists to encourage more middle school students to major in math and science when they go to college. The organizers o

matrenka [14]

Answer:

Item (D)

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In general, when comparing with the simple random sample, we realize that stratified random sampling has the advantage of increasing accuracy and decreasing variability.

In the question, we have two strata: female students and male students. On each one of the strata, a random sample of 25 names was made in the list.

7 0

3 years ago

I need some help on this problem

wolverine [178]

437 is your answer
______
3)131.1
- 12
____
11
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______
21
- 21
______
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5 0

3 years ago

Add 1 1/3 + (−5/6) = ?

Aleks [24]

1 1/3 = 4/3 (because (3 * 1 + 1) / 3)

We need both parts of sum to have common denominator.
Second part have denominator = 6.
When we multiply nominator and denominator of first part by 2 we get 8/6 (what is legit operation on fractions)

Now easily add:
8/6 + (- 5/6) = 8/6 - 5/6 = 3/6 (here we can divide both nominator and denominator by 3 to get "nicer" result) = 1/2

4 0

3 years ago