You take alll the answers and just divide each one
There are 8 weeks and 18 books. therefore you would multiply these numbers together.
the answer would be 144 different combinations.
not sure about the permutation or combination notation, but I got you on the first part!
Answer:
$7.34
Step-by-step explanation:
To compute sum of dollars that are not whole numbers. Using the sum of$5.89 and$1.45 as an illustration :
$5.89 + $1.45
Taking the whole numbers first:
$5 + $1 = $6
Take the sum of the decimals :
$0.89 + $0.45 = $1.34
Sum initial whole + whole of sum of decimal
$6 + $1 = $7
Remaining decimal : $1.34 - $1 = $0.34
$7 + $0.34 = $7.34
The correct answer is: " √x − <span>2√b " .
</span>_________________________________________________________
The "conjugate" of " √x + 2√b " is: " √x − 2√b " .
_________________________________________________________
Explanation:
_________________________________________________________
In an expression with 2 (TWO) terms; that is, in a "binomial expression",
the "conjugate" of that expression refers to that very expression — with the "sign" in between those two terms—"reverse" (e.g. "minus" becomes "plus" ; or, "plus" becomes "minus" .) .
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→ So: We are given: " <span>√x + 2√b " .
</span>
→ Note that this is a "binomial expression" ;
→ that is, there are 2 (TWO) terms: " <span>√x " ; and: " 2√b " .
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To find the "conjugate" of the given binomial expression:
</span>→ " <span>√x + 2√b " ;
</span>→ We simply change the "+" {plus sign} to a "<span>−" {minus sign} ; and rewrite:
___________________________________________________________
</span>→ " √x − 2√b " ;
→ which is the "conjugate" ; and is the correct answer:
___________________________________________________________
→ " √x − 2√b " ; is the "conjugate" of the expression: " <span>√x + 2√b " .
___________________________________________________________
</span>→ {that is: " √x − 2√b " ; is the conjugate.}.
___________________________________________________________
<em>The answer is ![\sqrt[3]{ 5^{7} }](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7B%205%5E%7B7%7D%20%7D%20)
</em>The reason we get this answer is because when you are converting from exponential form, to radical form you always place the numerator as our constant's exponent in the radical <em>(
is called the radicand because it is located in the radical)</em> and the denominator in front of the radical, where it would be called the index.
<em>Here's what a formula would look like:</em> ![( \sqrt[n]{x} ) ^{q}=x^{ \frac{p}{q} }](https://tex.z-dn.net/?f=%28%20%5Csqrt%5Bn%5D%7Bx%7D%20%29%20%5E%7Bq%7D%3Dx%5E%7B%20%5Cfrac%7Bp%7D%7Bq%7D%20%7D%20)
Thank you for your question! I hope this helped! Have an amazing day and feel free to let me know if I can help you further! :D
