Answer:
unearned service revenue 7,500 DEBIT
service revenue 7,500 CREDIT
Explanation:
the job is complete on July 31th
so <em>we write-off the unearned service reveue</em>
and <em>we recognize the service revenue </em>for the whole amount of the contract
The cash receipt occurs on March 1st so w edon't haveto post anythign related to cash on July 31th.
the unearned revenue account is used first because the business has the obligation of perform the job or return the cash. So it is a liablity until the job is completed
Answer:
B.
Explanation:
You do not need collateral to be given an unsecured loan.
Answer: No interest will be paid
Explanation:
Once full payment is made before the due repayment date on credit card, interest is not charged.
Answer:
The company should produce 7,500 bread machines to maximize profit
Explanation:
Given:
Toaster Ovens Bread Machines
Sales Price per unit 60 135
Less: variable cost per unit 38 75
Contribution Margin per unit 22 60
Machine hours per unit 1 2
Now,
Contribution Margin per Machine Hour = 
thus,
Contribution Margin per Machine Hour 22 30
Since,
The Contribution Margin per Machine Hour for the bread is more, therefore to maximize profits the kitchen company should produce Breads machines.
also,
Number of units to be produced = 
= 
= 7,500 units
Answer:
A) R(x) = 120x - 0.5x^2
B) P(x) = - 0.75x^2 + 120x - 2500
C) 80
D) 2300
E) 80
Explanation:
Given the following :
Price of suit 'x' :
p = 120 - 0.5x
Cost of producing 'x' suits :
C(x)=2500 + 0.25 x^2
A) calculate total revenue 'R(x)'
Total Revenue = price × total quantity sold, If total quantity sold = 'x'
R(x) = (120 - 0.5x) * x
R(x) = 120x - 0.5x^2
B) Total profit, 'p(x)'
Profit = Total revenue - Cost of production
P(x) = R(x) - C(x)
P(x) = (120x - 0.5x^2) - (2500 + 0.25x^2)
P(x) = 120x - 0.5x^2 - 2500 - 0.25x^2
P(x) = - 0.5x^2 - 0.25x^2 + 120x - 2500
P(x) = - 0.75x^2 + 120x - 2500
C) To maximize profit
Find the marginal profit 'p' (x)'
First derivative of p(x)
d/dx (p(x)) = - 2(0.75)x + 120
P'(x) = - 1.5x + 120
-1.5x + 120 = 0
-1.5x = - 120
x = 120 / 1.5
x = 80
D) maximum profit
P(x) = - 0.75x^2 + 120x - 2500
P(80) = - 0.75(80)^2 + 120(80) - 2500
= -0.75(6400) + 9600 - 2500
= -4800 + 9600 - 2500
= 2300
E) price per suit in other to maximize profit
P = 120 - 0.5x
P = 120 - 0.5(80)
P = 120 - 40
P = $80
