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1 year ago

Find the value of: (3/4)² a.9/16 b.6/8 c.6/4 d.9/4

Mathematics

2 answers:

Lemur [1.5K]1 year ago

7 0

Answer:

Step-by-step explanation:

(3/4) to the power of 2 means to multiply it by itself and so, 3/4 times itself is 9/16

Harrizon [31]1 year ago

3 0

Answer:

This is a - $\dfrac{9}{16}$

Step-by-step explanation:

Hello

$\large\displaystyle\text{$\begin{gathered} \sf Apply \ the \ third \ exponent \ rule-: \bigg(\dfrac{x}{y}\bigg)^m=\dfrac{x^m}{y^m} \end{gathered}$}}$

Solve-:

$\large\displaystyle\text{$\begin{gathered} \sf \bigg(\dfrac{x}{y}\bigg)^2= \dfrac{3^2} {4^2} =\boxed{\sf{\frac{9}{16}}} \end{gathered}$ }}$

$\pmb{\tt{done \ !!}}$

$\orange\hspace{300pt}\above2$

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Help please thank you guys! Really appreciate it

dalvyx [7]

Answer:

Explanation:

Radius = C/2π

C is 6.28 and 2*pi is also 6.28

So 6.28/6.28 = 1.

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3 years ago

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Wyatt analyzed the data from his science experiment and found that the MAD was greater than the IQR.

kotykmax [81]

Answer:

C: The average of the data is a closer to the least value than it is to the greatest value

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2 years ago

A piece of cardboard has the dimensions (x + 15) inches by (x) inches with the area of 60 in 2 . Write the quadratic equation th

pochemuha

Answer:

$x^2 + 15x - 60 = 0$

The actual dimension is 18.28 by 3.28

Step-by-step explanation:

Given

Dimension:

$(x + 15)\ by\ x$

$Area = 60in^2$

Required

Determine the quadratic equation and get the possible values of x

Solving (a): Quadratic Equation.

The cardboard is rectangular in shape.

Hence, Area is calculated as thus:

$Area = Length * Width$

$60= (x + 15) * x$

Open Bracket

$60= x^2 + 15x$

Subtract 60 from both sides

$x^2 + 15x - 60 = 0$

<em>Hence, the above represents the quadratic equation</em>

Solving (b): The actual dimension

First, we need to solve for x

This can be solved using quadratic formula:

$x = \frac{-b \± \sqrt{b^2 - 4ac}}{2a}$

Where

$a = 1$

$b = 15$

$c = -60$

So:

$x = \frac{-b \± \sqrt{b^2 - 4ac}}{2a}$

$x = \frac{-15 \± \sqrt{15^2 - 4*1*-60}}{2*1}$

$x = \frac{-15 \± \sqrt{225 + 240}}{2}$

$x = \frac{-15 \± \sqrt{465}}{2}$

$x = \frac{-15 \± \21.56}{2}$

Split:

$x = \frac{-15 + 21.56}{2}$ or $x = \frac{-15 - 21.56}{2}$

$x = \frac{6.56}{2}$ or $x = \frac{-36.36}{2}$

$x = 3.28$ or $x = -18.18$

But length can't be negative;

So:

$x = 3.28$

The actual dimensions: $(x + 15)\ by\ x$ is

$Length =3.28 +15$

$Length =18.28$

$Width = x$

$Width =3.28$

<em>The actual dimension is 18.28 by 3.28</em>

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3 years ago

Given the function f(x) = 0.3(4)x, what is the value of f−1(6)?

timofeeve [1]

Answer in 2.161 tell me if i made a mistake.

8 0

2 years ago

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How do we solve this?

Murljashka [212]

Answer:

f(x)=11+7√x

f'(x)=7/(2x^(1/2))

putting x=1

f'(1) = 7/(2×1^(1/2))

= 7/2 = 3.5

putting x=2

f'(2) = 7/(2×2^(1/2))

= 7/(2×√2)

= 7√2/4

= 2.47 (rounded to the nearest hundredth)

f'(3) = 7/(2×3^(1/2))

= 7/(2×√3)

= 7√3/6

= 2.02 (rounded to the nearest hundredth)

3 0

3 years ago