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iVinArrow [24]
3 years ago
14

How do we solve this?

Mathematics
1 answer:
Murljashka [212]3 years ago
3 0

Answer:

f(x)=11+7√x

f'(x)=7/(2x^(1/2))

putting x=1

f'(1) = 7/(2×1^(1/2))

= 7/2 = 3.5

putting x=2

f'(2) = 7/(2×2^(1/2))

= 7/(2×√2)

= 7√2/4

= 2.47 (rounded to the nearest hundredth)

f'(3) = 7/(2×3^(1/2))

= 7/(2×√3)

= 7√3/6

= 2.02 (rounded to the nearest hundredth)

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This must be on the moon as the acceleration due to gravity in this equation must be around 1/8 that on earth. :)  Anyway...

h=-2t^2+9t+11

A)

dh/dt=-4t+9, when velocity, dh/dt=0, it is the maximum height reached

dh/dt=0 only when 4t=9, t=2.25 seconds

h(2.25)=21.125 ft  (21 1/8 ft)

B)

As seen in A), the time of maximum height was 2.25 seconds after the squirrel jumped.

C)

The squirrel reaches the ground when h=0...

0=-2t^2+9t+11

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-2t(t+1)+11(t+1)=0

(-2t+11)(t+1)=0, since t>0 for this problem...

-2t+11=0

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4 0
3 years ago
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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

Part A.

The surface area of each figure is the sum of the end area and the lateral area.

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  S = (2)(πr²) +2πrh = 2πr(r +h)

  S = 2π(5 cm)(5 cm +10 cm) =150π cm² ≈ 471.2 cm²

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Part B.

Surface area is useful in the real world wherever products are made from sheets of material or wherever coverings are applied.

Carpeting or other flooring, paint, wallpaper are all priced in terms of the area they cover, for example.

The amount of material used to make containers in the shapes shown will depend on the area of these containers (and any material required for seams).

6 0
3 years ago
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Answer:

Step-by-step explanation:

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