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iVinArrow [24]
2 years ago
14

How do we solve this?

Mathematics
1 answer:
Murljashka [212]2 years ago
3 0

Answer:

f(x)=11+7√x

f'(x)=7/(2x^(1/2))

putting x=1

f'(1) = 7/(2×1^(1/2))

= 7/2 = 3.5

putting x=2

f'(2) = 7/(2×2^(1/2))

= 7/(2×√2)

= 7√2/4

= 2.47 (rounded to the nearest hundredth)

f'(3) = 7/(2×3^(1/2))

= 7/(2×√3)

= 7√3/6

= 2.02 (rounded to the nearest hundredth)

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Of the 85% of the students in a class who studied for a test,75% passed the test.Of the 15% of the students who didn't study,30%
galina1969 [7]
Probability works for any given number, so we will assume there are 100 students. Of those 100, 85 of them studied. Since 75% of 85 students passed, we will multiply 85 by 0.75. This gives us 60. So of the students who studied, 60 of them passed. Of the 15 students that didn’t study, 30 percent passed. So we multiply 15 by 0.3. This gives us 4.5 students. Add up 60 and 4.5, and you get 64.5. The probability of passing is 64.5%. If you want to round up, it would be 65%. If you want to round down, it would be 64%. But the most precise answer is 64.5%.
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2 years ago
Multiply: (-1-3i)(-5 - 4i)
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The answer is -7+19i because of the procedure used in math
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3 years ago
Find the measures of EAF DAE and CAD
sdas [7]
You have to build an equation to find the answer,

angles in a straight line add upto 180° 
so your equation would be,

12x+30°=180°
      -30    -30
=12x=150°
   ÷12  ÷12
=x=12.5°

now find the measures of the angles by using 12.5 as x.

angle EAF= 2x
                 =2×12.5
                 =25° degrees

angle DAE= 4x
                 =4×12.5
                 =50°degrees

angle CAD=6x
                 =6×12.5
                 =75°degrees

check,
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7 0
2 years ago
The five-number summary of the ages of passengers on a cruise ship is listed below. Min 1 Q1 20Median 29 Q3 38Max 80 Consider th
Eddi Din [679]

Answer: b. Only statement (ii) is correct.

Step-by-step explanation:

The given five-number summary of the ages of passengers on a cruise ship is listed below.

Min 1    Q_1 20     Median 29     Q_3 38         Max 80

Inter-quartile range = IQR=Q_3-Q_1=38-20=18

  • According to the 1.5(IQR) criterion for outliers : An data value is an outlier if it lies below Q_1 - 1.5(IQR) or  above Q_3 + 1.5(IQR).

Here , Q_1 - 1.5(IQR) =20-1.5(18)=-7

Q_3 + 1.5(IQR)=38+1.5(18)=65

Since the minimum value> Q_1 - 1.5(IQR) ( ∵ 1 > -7)

It means there is no value below Q_1 - 1.5(IQR)  , so there is no low -outlier.

⇒ Statement (i) "here is at least one passenger whose age is a low outlier. " is false.

But the maximum value > Q_3 + 1.5(IQR) (∵  85 > 65)

It means there are values above Q_3 + 1.5(IQR).

⇒Statement (ii) "There is at least one passenger whose age is a high outlier" is true.

Hence, the correct answer is b. Only statement (ii) is correct.

8 0
3 years ago
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