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tatuchka [14]
2 years ago
10

Ch circle shows AB that measures 60°?

Mathematics
1 answer:
chubhunter [2.5K]2 years ago
7 0

Step-by-step explanation:

there are a lot of typos and missing info in your problem and answer option definition.

based on what I understood the answer should be

"the second answer option".

this is where A and B have an arc angle (or inner angle at the center of the circle) of 60°.

one could see the 3rd answer to be right too, as the angle between A and B at Y is also 60°.

but I don't think this is really the meaning of this question here.

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Rylee saved $9 on a $60 pair of<br> shoes. What percent did she save?
Ilia_Sergeevich [38]

Answer:

15%

Step-by-step explanation:

9/60=3/20=15%

8 0
2 years ago
11) The measure of each interior angle of a regular 11-sided polygon is
Svet_ta [14]

Answer:

Step-by-step explanation:

Always , sum of exterior angle of any polygon  = 360

sum of exterior angle of 11- sided polygon  = 360

Measurement of  an exterior angle of 11-sided polygon  = 360/11

                                                 = 32.73

Measurement of  an interior angle of 11-sided polygon = 180 - 32 8/11

= 180 - 32.73= 147.27

7 0
3 years ago
Nadia swims at a rate of 50 meters per minute. Create a function f, where f(n) gives the number of meters Nadia swims given the
ivann1987 [24]

Answer: i dont know sorry

Step-by-step explanation:

6 0
3 years ago
What is the following quotient?
mamaluj [8]

Answer:

A.2(3^{\frac{1}{3}})-\sqrt[3]{18}

Step-by-step explanation:

We are given that

\frac{6-3(\sqrt[3]{6}}{\sqrt[3]{9}})

We have to find the quotient.

\frac{6}{\sqrt[3]{9}}-3(\frac{\sqrt[3]{6}}{\sqrt[3]{9}})

\frac{2\times 3}{\sqrt[3]{3^2}}-3(\frac{\sqrt[3]{3\times 2}}{\sqrt[3]{3^2}})

2\times\frac{3}{3^{\frac{2}{3}}}-3(\frac{2^{\frac{1}{3}}\times 3^{\frac{1}{3}}}{3^{\frac{2}{3}}})

Using the property

(ab)^n=a^n\cdot b^n

2\times 3^{1-\frac{2}{3}}-3(2^{\frac{1}{3}}\times 3^{\frac{1}{3}-\frac{2}{3}})

Using the property

\frac{a^x}{a^y}=a^{x-y}

2(3^{\frac{1}{3}})-3(2^{\frac{1}{3}}\times 3^{-\frac{1}{3}})

2(3^{\frac{1}{3}})-2^{\frac{1}{3}}\times 3^{1-\frac{1}{3}}

2(3^{\frac{1}{3}})-2^{\frac{1}{3}}\times 3^{\frac{2}{3}}

2(3^{\frac{1}{3}})-2^{\frac{1}{3}}\times \sqrt[3]{3^2}

2(3^{\frac{1}{3}})-2^{\frac{1}{3}}\times \sqrt[3]{9}

2(3^{\frac{1}{3}})-\sqrt[3]{2\times 9}

2(3^{\frac{1}{3}})-\sqrt[3]{18}

Hence, the quotient of \frac{6-3(\sqrt[3]{6}}{\sqrt[3]{9}}) is given by

2(3^{\frac{1}{3}})-\sqrt[3]{18}

Option A is correct.

4 0
3 years ago
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It is 7x+21 and 7x+1 x 21
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