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3 years ago

F (x) = 3x +2 fine the inverse of the function

Mathematics

1 answer:

Hitman42 [59]3 years ago

7 0

.................F^-1 (x) =x/3-2/3 .................

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Integers: 5[152-{7-8(9-2)}] please answer this

Dmitry [639]

Answer:

1005

Step-by-step explanation:

1005

solve () {} []

ksjsksks

3 0

3 years ago

The ratio of boys to girls in math is 9 to 12. Write this ratio to girls in simplest form as a fraction.

andre [41]

Answer:

3/4

Step-by-step explanation:

you can make it into a fraction just putting it like this 9/12

well 12 - 9 = 3

so we divide by it

9÷3 = 3

12÷3 = 4

lastly you put these as a fraction

3/4

I hope this helps :)

4 0

3 years ago

Convert the scale to a unit rate. 1/4 in = 3/4 mi

ser-zykov [4K]

There are 190080 1/4 inch in 3/4 mile. Hope this helps.

4 0

3 years ago

Which data set could be represented by the box plot shown below? A horizontal boxplot is plotted along a horizontal axis marked

ludmilkaskok [199]

Answer:

(B)1,3,6,8,10,12,13,13,16,18,19

Step-by-step explanation:

In the box plot:

A left whisker extends from 1 to 6, therefore, the least value is 1.

The box extends from 6 to 16 and is divided into 2 parts by a vertical line segment at 12. Therefore:

The lower quartile is 6
The median is 12
The upper quartile is 16

The right whisker extends from 16 to 19, therefore the highest value is 19.

The set of data that satisfies these conditions where the numbers in bold are the 5- number summary is:

1,3,6,8,10,12,13,13,16,18,19

The correct option is B.

8 0

3 years ago

Use green’s theorem to evaluate

Georgia [21]

By Green's theorem (all the conditions are met), we have

$\displaystyle \int_C \sqrt y \, dx + \sqrt x \, dy = \iint_D \frac{\partial(\sqrt x)}{\partial x} - \frac{\partial(\sqrt y)}{\partial y} \, dx \, dy$

where D is the interior of the path C, or the set

$D = \left\{ (x, y) : 0 \le y \le \dfrac{x^2}2 \text{ and } 0 \le x \le 2 \right\}$

So, the line integral reduces to the double integral,

$\displaystyle \frac12 \int_0^2 \int_0^{\frac{x^2}2} x^{-\frac12} - y^{-\frac12} \, dy \, dx$

$\displaystyle = \frac12 \int_0^2 x^{-\frac12}\left(\frac{x^2}2\right) - 2\left(\frac{x^2}2\right)^{\frac12} \, dx$

$\displaystyle = \frac12 \int_0^2 \frac12 x^{\frac32} - \sqrt 2 \, x \, dx$

$\displaystyle = \frac14 \int_0^2 x^{\frac32} - 2\sqrt 2 \, x \, dx$

$\displaystyle = \frac14 \left(\frac25\cdot2^{\frac52} - \sqrt2\cdot2^2\right) = \boxed{-\frac{3\sqrt2}5}$

5 0

2 years ago