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DanielleElmas [232]
3 years ago
15

F (x) = 3x +2 fine the inverse of the function

Mathematics
1 answer:
Hitman42 [59]3 years ago
7 0
.................F^-1 (x) =x/3-2/3 .................
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Helpppppppppppooooo :p
garri49 [273]

Answer:

1) c. 10

2) a. 1 and 18

3) d. 17

4) I think it's actually 12 but I don't know

8 0
3 years ago
2(v–11) please help me solve this
nika2105 [10]

Answer: 2v-22

Step-by-step explanation:

2(v)=2v

2(-11)= -22

2v - 22

6 0
3 years ago
Avery planned a circular garden and path as shown below. The radius of the garden is 4 feet and the path around the garden is 2
Digiron [165]

Answer:

Option C) 113.0 feet squared

Step-by-step explanation:

We are given the following in the question:

Radius of circular garden = 4 feet

Length of path around garden =  2 feet

We have to find the total area of garden and path.

The garden and path together makes a bigger circle with radius

R = 4 + 2 = 6\text{ Feet}

Area of garden and path =

A = \pi R^2

Putting values, we get,

A  = 3.14\times (6)^2 = 113.04\\A \approx = 113.0\text{ square feet}

Thus, the correct answer is

Option C) 113.0 feet squared

8 0
3 years ago
Read 2 more answers
J.J.Bean sells a wide variety of outdoor equipment and clothing. The company sells both through mail order and via the internet.
melamori03 [73]

Answer:

99% confidence interval for the true mean difference between the mean amount of mail-order purchases and the mean amount of internet purchases is [$(-31.82) , $12.02].

Step-by-step explanation:

We are given that a random sample of 16 sales receipts for mail-order sales results in a mean sale amount of $74.50 with a standard deviation of $17.25.

A random sample of 9 sales receipts for internet sales results in a mean sale amount of $84.40 with a standard deviation of $21.25.

The pivotal quantity that will be used for constructing 99% confidence interval for true mean difference is given by;

                      P.Q.  =  \frac{(\bar X_1-\bar X_2)-(\mu_1-\mu_2)}{s_p \times \sqrt{\frac{1}{n_1}+\frac{1}{n_2} } }  ~ t__n_1_+_n_2_-_2

where, \bar X_1 = sample mean for mail-order sales = $74.50

\bar X_2 = sample mean for internet sales = $84.40

s_1 = sample standard deviation for mail-order purchases = $17.25

s_2 = sample standard deviation for internet purchases = $21.25

n_1 = sample of sales receipts for mail-order purchases = 16

n_2 = sample of sales receipts for internet purchases = 9

Also,  s_p =\sqrt{\frac{(n_1-1)\times s_1^{2}+(n_2-1)\times s_2^{2} }{n_1+n_2-2} }  =  \sqrt{\frac{(16-1)\times 17.25^{2}+(9-1)\times 21.25^{2} }{16+9-2} } = 18.74

The true mean difference between the mean amount of mail-order purchases and the mean amount of internet purchases is represented by (\mu_1-\mu_2).

Now, 99% confidence interval for (\mu_1-\mu_2) is given by;

             = (\bar X_1-\bar X_2) \pm t_(_\frac{\alpha}{2}_)  \times s_p \times \sqrt{\frac{1}{n_1} +\frac{1}{n_2}}

Here, the critical value of t at 0.5% level of significance and 23 degrees of freedom is given as 2.807.

          = (74.50-84.40) \pm (2.807  \times 18.74 \times \sqrt{\frac{1}{16} +\frac{1}{9}})

          = [$-31.82 , $12.02]

Hence, 99% confidence interval for the true mean difference between the mean amount of mail-order purchases and the mean amount of internet purchases is [$(-31.82) , $12.02].

5 0
3 years ago
Winton wants to find the volume of a cube. He uses the formula for volume of a cube V= <img src="https://tex.z-dn.net/?f=%20%7Bs
N76 [4]
0.125 cubic centimeters.
3 0
3 years ago
Read 2 more answers
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