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goblinko [34]
3 years ago
11

For questions 6a & 6b, calculate the mean for each group: 6a) Textbook A 6b) Textbook B Mean: ______________ Mean: _________

_____ 6) Which class performed better? 7) If the standard deviation for Class A was 26.3 and the standard deviation for Class B was 8.5, which class was more consistent?
Mathematics
1 answer:
lisabon 2012 [21]3 years ago
3 0

Answer:

44 52 95 76 13 94 83 72 55 81 22 25 64

The mean is: 59.7

65 72 48 63 68 59 68 62 75 79 81 72 64

The mean is: 67.4

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PLZ HELP ASAP WILL MARK BRAINLIEST
Mkey [24]

DEF will be 2.68

EF will be .67

3 0
3 years ago
A. Evaluate the polynomial
sdas [7]

Answer:

a) y = x³− 5x² + 6x + 0.55 at x = 1.37.

Use 3-digit arithmetic with chopping. Evaluate the percent relative round-off error.

-1.183%

b. Express y as y = ((x − 5)x + 6)x + 0.55 (this is the same equation). Use again 3-digit arithmetic with chopping. Evaluate the percent relative round-off error and compare with part (a). Make the conclusion about which form of the polynomial is superior.

-0.161%

Comparing part a and b together, part b is more superior because the percent(%) error is smaller when compared to part a

Step-by-step explanation:

a) y = x³− 5x² + 6x + 0.55 at x = 1.37.

Use 3-digit arithmetic with chopping. Evaluate the percent relative round-off error.

Let's evaluate before applying the 3 digit arithmetic chopping rule

y = 1.37³ - 5 × 1.37² + 6 × 1.37 + 0.55

y = 1.956853

Let evaluate each components of the polynomial one by one

Note that: 3-digit arithmetic chopping means to approximate chop off or remove number after the 3 significant figures.

y = x³− 5x² + 6x + 0.55 at x = 1.37.

x³ = 1.37³ = 2.571353

≈ 2.57

x² = 1.37² = 1.8769

≈ 1.88

5x² = 1.87 × 5

= 9.35

x = 1.37

6x = 1.37 × 6

6x = 8.22

Evaluating the polynomial

y = 2.57 - 9.38 + 8.22 + 0.55

y = 1.98

The percent relative round-off error =

1.956853 - 1.98/1.956853 × 100

= -1.183%

b. Express y as y = ((x − 5)x + 6)x + 0.55 (this is the same equation). Use again 3-digit arithmetic with chopping. Evaluate the percent relative round-off error and compare with part (a). Make the conclusion about which form of the polynomial is superior.

y = ((x − 5)x + 6)x + 0.55

Evaluating with the 3 digit chop off rule is applied

= ((1.37 - 5)1.37 + 6)1.37 + 0.55

=( 1.8769 - 6.85) + 6) 1.37 + 0.55

= (- 4.9731 + 6 )1.37 + 0.55

= 1.0269 × 1.37 + 0.55

= 1.406853

= 1.956853.

≈ 1.96

Note in: evaluating before applying the 3 digit arithmetic chopping rule

y = 1.37³ - 5 × 1.37² + 6 × 1.37 + 0.55

y = 1.956853

The percent relative round-off error

1.956853 - 1.96/1.956853 × 100

= -0.161%

Comparing part a and b together, part b is more superior because the percent(%) error is smaller when compared to part a

3 0
3 years ago
2 points) Suppose w=xy+yzw=xy+yz, where x=et, y=2+sin(t)x=et, y=2+sin⁡(t), and z=2+cos(3t)z=2+cos⁡(3t). A ) Use the chain rule t
Olenka [21]

Answer:

\frac{\partial w}{\partial t}  = y(e^t) +(x+z)*(cos(t))  - 3y*sin(3t)

Step-by-step explanation:

First, note that

\frac{\partial x}{\partial t}  = e^{t} \\\frac{\partial y}{\partial t}  = cos(t)\\

And using the chain rule in one variable

\frac{\partial z}{\partial t}  = -3sin(3t)

Now remember that the chain rule in several variables sates that

\frac{\partial w}{\partial t}  = \frac{\partial w}{\partial x} * \frac{\partial x}{\partial t} + \frac{\partial w}{\partial y} * \frac{\partial y}{\partial t} + \frac{\partial w}{\partial z} * \frac{\partial z}{\partial t}

Therefore the chain rule in several variables would look like this.

\frac{\partial w}{\partial t}  = y(e^t) +(x+z)*(cos(t))  - 3y*sin(3t)

6 0
3 years ago
Read 2 more answers
A mutual funds company’s newsletter says, "A well-diversified portfolio includes assets with low correlations." The newsletter i
LekaFEV [45]

Answer:

The less the correlation between two variables means the more different their output is.

A.) If Rachel wants to diversify her investment by investing on bonds that do not closely follow the returns on the bond. then she should invest in the stocks with low correlation with bonds. I.e: small cap stocks.

B.) Similarly, due to low correlation, small cap bonds will increase ( comparatively to large cap bonds) as the return on her bonds wil drop and vice versa.

8 0
2 years ago
Just help me on 6 and 7 please
TEA [102]
6) 9/4 divided by 5/8
9/4x5/8
9x8/4x5
72/4/5
72/20
18/5
Answer: 18/5

7) 2 1/2 divided by 4 1/2
2x2+1/2 divided by 4 1/2
4+1/2 divided by 4 1/2
5/2 divided by 4 1/2
5/2 divided by 8+1/2
5/2 divided by 9/2
5/2x9/2
5/2x2/9
5x1/9
5/9
Answer: 5/9
4 0
2 years ago
Read 2 more answers
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