9514 1404 393
Answer:
a) 3.491 in/s
b) 3.333 RPM
c) 0.349 rad/s
Step-by-step explanation:
We know the arc length for a given radius and angle is ...
s = rθ
so the linear speed along the arc is ...
s' = rθ' = (10 in)(20π/180 rad/s) = 10π/9 in/s ≈ 3.491 in/s
__
The rotation rate of 20°/s is an angular velocity of ...
(20°/s)(60s/min)(1 rev/360°) = 3.333 RPM
__
In the first part, we found the angular speed to be π/9 radians/sec. That's about ...
π/9 rad/s ≈ 0.349 rad/s
Answer is 108 pages. 1/3 of an hr is 20 min. 20*3=60 which is an hr. 3+3=6. So then you get 6*18=108.
Answer:
Step-by-step explanation:

Answer:
1 and 8 are alternate exterior
8 and 5 are corresponding
3 and 2 are vertical
6 and 3 are alternate interior
16 n^2 -10n + 129 = 8n^2 -8
We collect the terms:
8n^2 -10n + 137 = 0
The steps for completing the square:
1) Move the "non X" (or "non N") term to the right:
8n^2 -10n = -137
<span>2)<span> Divide the equation by the coefficient of N² which in this case is 8
n^2 -1.2n = </span></span><span><span>-17.125
</span>
3) Take the coefficient of "N"; divide it by 2; square it; add it to both sides of the equation.
-1.2 / 2 = -.6
-.6^2 = .36
</span>
n^2 -1.2n +.36 = <span>-17.125
+.36
Take the square root of both sides:</span>
(n-.6)*(n-.6) = sq root(
<span>
<span>
<span>
-16.765
</span>
</span>
</span>
)
That's about as far as I can go.