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3 years ago

. identify the binomial a. x2 b. x2 - 4x 2 c. x2 - 4 d. 2x2 3x - 1 y

Mathematics

2 answers:

tino4ka555 [31]3 years ago

6 0

Answer: $x^2 - 4$

Step-by-step explanation:

Since a Binomial is an algebraic expression of the sum or the difference of two terms.

Therefore, For a binomial an expression must contain exactly two terms.

In a) $x^2$ there is only one term therefore it is not the Binomial.

In a) $x^2-4x^2 = -3x^2$ , there is only one term therefore it is not the Binomial.

In a) $x^2-4$ there is exactly two terms therefore it is a Binomial.

In a) $2x^2+3x-1y$ there are three terms therefore it is not the Binomial.

kondaur [170]3 years ago

6 0

Binomial has 2 terms when simplified

a. x^2, only 1 term
b. x2-4x^2=-3x^2, 1 term
c. x^2-4 , 2 terms, binomial
d. 2x^2+3x-1y, 3 terms, trinomial

answer si C

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Answer:

Step-by-step explanation:

This requires some serious work before we even begin. First off, we will convert the km to meters:

32 km = .032 m

46 km = .046 m

And then we have to deal with the angle given as 40 degrees west of north. An angle 40 degrees west of north "starts" at the north end of the compass and moves towards the west (towards the left in a counterclockwise manner) 40 degrees. That means that the angle that is made with the negative x axis is a 50 degree angle. BUT the way angles are measured in standard form are from the positive x-axis, therefore:

40 degrees west of north = 50 degrees with the negative x axis = 130 degrees with the positive x axis. 130 is the angle measure we use. Phew! Now we're ready to start. Adding vectors requires us to use the x and y components of vectors in order to add them.

$A_x=.032cos90.0$ so

$A_x=0$ (the 90 degrees comes from "due north")

$B_x=.046cos130$ so

$B_x=-.030$ and if we add those to get the x component of the resultant vector, C:

$C_x=-.030$ And onto the y components:

$A_y=.032sin90.0$ so

$A_y=.032$

$B_y=.046sin130$ so

$B_y=.035$ and if we add those together to get the y component of the resultant vector, C:

$C_y=.067$ Note that since $C_x$ is negative and $C_y$ is positive, the resultant angle (the direction) will put us into QII.

We find the magnitude of C:

$C_{mag}=\sqrt{(-.030)^2+(.067)^2}$

We will round this after we take the square root to the thousandths place.

$C_{mag}=.073m$ and now for the angle:

$\theta=tan^{-1}(\frac{.067}{-.030})$ which gives us an angle measure of -67, but since we are in QII, we add 180 to that to get that, in sum:

The magnitude of the resultant vector is .073 m at 113°

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3 years ago

BRAINLIEST TO CORRECT ANSWER!!!!

just olya [345]

Answer:

As Per Provided Information

Diameter of Garden 12 yards

Radius of Garden will be 12/2

Radius of Garden will be 6 cm

We have been asked to find the area of the circular garden .

Formula Used here

$\underline{\boxed {\bf \: Area_{(Garden)} \: = \pi {r}^{2}}}$

Just put the value and let's calculate the area of circular garden .

$\qquad \longrightarrow\sf \: Area_{(Garden)} \: = 3.14 \times {6}^{2} \\ \\ \\ \qquad \longrightarrow\sf \: Area_{(Garden)} \: = 3.14 \times 36 \\ \\ \\ \qquad \longrightarrow\sf \: Area_{(Garden)} \: = 113.04 \: {yard}^{2}$

Therefore,

Area of circular garden is 113.04 yard².

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3 years ago

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