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guapka [62]
2 years ago
10

Please help

Mathematics
1 answer:
nata0808 [166]2 years ago
6 0

Answer:

i believe the answer is 3^2(-2)^6/ 5^4

Step-by-step explanation:

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kow [346]
The answer is c hope this helps
3 0
3 years ago
Read 2 more answers
Can you simplify all of these questions please
VMariaS [17]
<h3>step by step:</h3>

-3(p-1)+9p+2

  • -3p+3+9p+2
  • -3p+9p,+3+2
  • 6p+5

10-4(m+1)

  • 10-4m-4
  • 6-4m
  • 2(3-2m)

4g-2g-3(g-2)

  • 4g-2g-3g+6
  • 2g-3g+6
  • -g+6

hope it helps

stay safe healthy and happy.

6 0
3 years ago
Read 2 more answers
The floor of a restaurant is a square of sides 28 cm. The floor covered with square tiles of sides 40 cm. Calculate the total nu
andrew11 [14]

Answer:

I'm going to calculate with sides 28 m

4,900 tiles used

Step-by-step explanation:

Area restaurant 28x28 = 784 m squared

each tile 40 cm = 0.4m

area of tile 0.4x0.4 =0.16

784/0.16 = 4,900

5 0
3 years ago
The heat in the house is set to keep the minimum and maximum temperatures (in degrees Fahrenheit) according to
spin [16.1K]

Answer:

B : 68.5°F and 76.5°F

I think sorry if i am wrong.

Step-by-step explanation:

3 0
2 years ago
Can the mean value theorum be applied to the function f(x)=1/x^2 on the interval [-2, 1]? Explain.
Temka [501]

Answer:

No, it can not be applied.

Step-by-step explanation:

f(x) = 1/x²

f(x) is a polynomial that is not continuous

As,

f(x) = 1/0 is undefines

Secondly, it is not differentiable (i.e. the derivative does not exists on the interval given)

Derivative of this function

f'(x) = (1)x^-2

       = -2x^(-2-1)

       = -2x^(-3)

       = -2/x³

      =  -2/x³

f'(0) = -2/0 is undefined

Thus, mean value theorem can not be applied.

7 0
4 years ago
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