All categories

2 years ago

What the answer is to this question as a fraction in lowest terms

Mathematics

1 answer:

Pachacha [2.7K]2 years ago

3 0

Hello from MrBillDoesMath!

Answer:

9 3/8

Discussion:

2 1/7 = 15/7

4 3/8 = 35/8

so the product

(2 1/7) * ( 4 3/8) =

15/7 * 35/8 =

15/7 * (7 * 5)/8 =

since 35 = 7*5. Cancel "7" in numerator\denominator to get

(15 * 5) / 8 =

75/8 =

9 3/8

Thank you,

MrB

You might be interested in

Darius deposits $300 into a new savings account. The account earns at a rate of 2.18% every 6 months. How much money does Darius

MAVERICK [17]

45.87= 2.18 plus 300 is 345.87 hope this is correct if not im soooo sorry

5 0

3 years ago

A square has side length of 9 in. If the area is doubled, what happens to the side length?

Alika [10]

Answer:

The side length is multiplied by $\sqrt{2}$

Step-by-step explanation:

we know that

The area of the original square is equal to

$A=9^{2}=81\ in^{2}$

If the area is doubled

then

The area of the larger square is

$A1=(2)81=162\ in^{2}$

Remember that

If two figures are similar, then the ratio of its areas is equal to the scale factor squared

Let

z ----> the scale factor

x ----> the area of the larger square

y ---> the area of the original square

$z^{2}=\frac{x}{y}$

we have

$x=162\ in\^{2}$

$y=81\ in\^{2}$

$z^{2}=\frac{162}{81}$

$z^{2}=2$

$z=\sqrt{2}$ ------> scale factor

therefore

The side length is multiplied by $\sqrt{2}$

7 0

2 years ago

Determine if the lines are parallel, perpendicular, or neither x-3y= 15 and y = -3+4

Alina [70]

If the second equation is y=-3x+4 then they would be parallel and I found that by turning the first equation into y=mx+b and you subtract x from both sides of the equation and get -3y=-x+15 and then you divide both sides of the equation by -3 to get the y by itself and that turns into y=1/3x-5 and since 1/3 is the reciprocal of -3 they are perpendicular.

7 0

3 years ago

What are the solutions to this equation?

ziro4ka [17]

$\displaystyle\\(x-4)^2=49\\\\(x-4)^2-49=0\\\\(x-4)^2-7^2=0\\\\(x-4-7)(x-4+7)=0\\\\(x-11)(x+3)=0\\\\x-11 = 0~~~\text{or}~~~x+3=0\\\\x-11=0~~~\implies~~~\boxed{x_1=11}\\\\x+3=0~~~\implies~~~\boxed{x_2=-3}\\\\\boxed{\bf The~solutions~are:~~x =11~~\text{or}~~x =-3}$

8 0

2 years ago

What is the correct answer

tiny-mole [99]

Take a look at all 3 expressions: numbers, terms, and exponents.

4, 8, and 6 all have a GCF of 2.

y^5, y^3, and y^2 have a GCF of y^2.

Therefore, the GCF is 2y^2. Removing it gets you:

2y^2(2y^3 + 4y - 3)

5 0

2 years ago