Unfortunately, your " 12×+9=10×1 " can be interpreted in more than one way. The symbol " × " should be used ONLY to indicate multiplication. Thus, " 12× " reads as ' 12x.' Then we have: 12x + 9 = 10. Unsure of what you meant by " 10×1". So I will treat your "10×1" as simply '10.'

Then we have 12x + 9 = 10, which reduces to 12x = 1 if we subtract 9 from both sides.

12x = 1 yields x = 1/12.

If this is not the result you expected, please go back to the original problem and share it as accurately as you can.

6 0

3 years ago

Which graph shows a negative rate of change for the interval 0 to 2 on the x-axis?

valentina_108 [34]

It seems that the four graphs are the same and they do not have a negative change rate in the interval 0 to 2 in the x-axis.

A negative change rate means that when x increases the value of the function (y) decreases; this is, the function is decreasing in the interval being estudied, which is the same that going downward.

So, you must look for in your graphs where the equation is going downward.

For example, in the graph attached, that happens in any interval from negative infitity to 1.5.

The vertex will help you to identify it.

Given that the graph goes downward from negative infinity to the vertex, any interval that includes that range will have negative change.

You must look for a parabola that opens upward and whose vertex is in x = 2.

Read more on Brainly.com - brainly.com/question/3774202#readmore

5 0

3 years ago

Read 2 more answers

At a race track you have the opportunity to buy a ticket that requires you to pick the first and second place horses in the firs

rewona [7]

Answer:

4032 different tickets are possible.

Step-by-step explanation:

Given : At a race track you have the opportunity to buy a ticket that requires you to pick the first and second place horses in the first two races. If the first race runs 9 horses and the second runs 8.

To find : How many different tickets are possible ?

Solution :

In the first race there are 9 ways to pick the winner for first and second place.

Number of ways for first place - $^9C_1=9$