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Novay_Z [31]
2 years ago
15

PLEASE ANSWER THIS AS FAST AS POSSIBLE AND AS FAST AS POSSIBLE! I WILL MARK BRAINLIEST! PLEASE!

Mathematics
1 answer:
REY [17]2 years ago
7 0
LINKEDAASASUAGEESSSSSSSSSSSXX
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The longest side of a triangle is 5 inches longer than the shortest side. The medium side is 2 inches longer than the shortest s
Rom4ik [11]
If we refer to the longest side as x and the shortest side as y and the medium side as z then we come up with this formation:

x+y+z= 22

y is shorter than x by 5 inches so y= x-5

z is longer than y by 2 inches therefore z= x-5 +2

therefore:
x+(x-5)+(x-5+2)=22
x+x-5+x-5+2=22
3x-8=22
3x= 22-8
3x=14
x=
\frac{14}{3}

replace x in y and z in previous formations
5 0
4 years ago
PrettPlease plsssss I beg of you sor
Naya [18.7K]

9514 1404 393

Answer:

  • The percentage of total votes received by Molly
  • 58%

Step-by-step explanation:

a) We don't know what your menu choices are. The question is asking for the percentage of total votes received by Molly.

__

b) The total number of votes is 21 +29 = 50. Molly's fraction is 29/50. Expressed as a percentage, that is ...

  29/50 × 100% = 58%

8 0
3 years ago
Spam e-mail containing a virus is sent to 1000 e-mail addresses. After 1 second, a recipient machine broadcasts 10 new spam e-ma
pickupchik [31]

Answer:

Answer explained below

Step-by-step explanation:

Spam e-mail containing a virus is sent to 1000 e-mail addresses. After 1 second, a recipient machine broadcasts 10 new spam e-mails containing the same virus, after which the virus disables itself on that machine. (1) Write a recursive definition (i.e. recurrence relation) to show how many spam emails will be sent out after n seconds. (2) Solve the recurrence relation. (3) How many e-mails are sent at the end of 20 seconds

1.START T=0.....

1000 EMAILS SENT AND RECEIVED BY 1000 M/CS.

T=1.....

EACH OF THE M/C SENDS 10 NEW MAILS ....

.................................

LET M[N] BE THE NUMBER OF MAILS SENT OUT AFTER N SECONDS.

SO , EACH OF THESE M/CS WILL SEND 10 MAILS IN NEXT 1 SECOND.

HENCE NUMBER OF MAILS SENT IN N+1 SECONDS=M[N+1]=

M[N+1]=10*M[N].......................1

THIS IS THE RECURRENCE RELATION.....

2.SOLUTION .....

M[N+1]=10M[N]=10*10M[N-1]=10*10*10M[N-2]=........

M(N+1)=[10^1][M(N)]=[10^2][M(N-1)]=[10^3][M(N-2)]=..........=[10^N][M(1)]=[10^(N+1)][M(0)]

M[N+1]=[10^(N+1)][1000]=[10^(N+1)][10^3]=[10^(N+4)]......................................2

THIS IS THE NUMBER OF MAILS SENT AFTER N+1 SECONDS .....OR ....

M[N]=[10^(N+3)].............................................3

..................IS THE SOLUTION FOR NUMBER OF MAILS SENT AFTER N SECONDS.....

3.AFTER N=20 SECONDS , THE ANSWER IS ....

M[20]=10^(20+3)=10^23

8 0
3 years ago
Read 2 more answers
There are 12 triangles and 3 squares. What is the simplest ratio of<br> squares to triangles?
grigory [225]
Squares : Triangles
3 : 12
Divide both sides by 3.
The simplest ratio is

1 : 4
4 0
3 years ago
Read 2 more answers
Help me please, thank you!
elena-s [515]
A is 3 square root 2
Since 3*6 is 18
Find the factors of 18
So we have 9 and 2
9 is a perfect square so it’s 3 with 2 inside radical
7 0
3 years ago
Read 2 more answers
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