Answer: could we see the expressions please?
Step-by-step explanation:
We assume the base is 12 in × 20 in, so its diagonal has length
... √(12² +20²) = √(144 +400) = √544 = 4√34 . . . inches
Then the tangent of the angle of interest is the ratio of the box height to the base diagonal:
... tan(α) = (7 in)/(4√34 in) ≈ 0.300123
The angle will be the arctangent of this value,
... α = arctan(7/√544) ≈ 0.291569 radians
Answer:
-21
Step-by-step explanation:
2-8 × 2-7 = 2-(8×2)-7
= 2-16-7
=-14-7
=-21
The maximum weight that could be held would be 32 pounds. or six five pound weights taking up 18 inches of space, and weighing 30 Lbs, and two one pound weights adding another two inches. You could achieve a greater weight if you had a weight of one-half inch, in which case you could take six 5 lb weights and 1 two pound weight, then you could add a half inch weight bringing the weight to over 32 inches. Since we don't have a half inch weight we can't raise the weight above 32lbs.
Answer: Parallel
Step-by-step explanation:
Set your -2x+10y=5 equation equal to y
-2x+10y=5
<u> -10y -10y</u>
-2x=5-10y
<u>-5 -5 </u>
<u>-2x-5</u>+<u>-10y</u>
-10 -10 -10
-1/5x-1/2=y
Now you can put your equations into your graphing calculator and examine the lines made
(if you dont have one search up <em>online graphing calculator</em> on google or your app store)
