Answer:
Step-by-step explanation:
a1 = 6
a2 = 10
a3 = 14
The next member of the sequence is 4 more than the current sequence. Therefore d = 4
a1 = 6
d = 4
n = 13
an = a1 + (n - 1)*d
an = 6 + (n - 1)*4
a_13 = 6 + 12*4
a_13 = 6 + 48
a_13 = 54
(12 2/3) divided by 8 = 19/12 or 1.58333333333333
If they sell the same amount next year and want to reach $1,500, they must higher the price. to do that, they can divide the $1500 by the number of agendas. Do the math yourself, its not very hard.
Hello!
To calculate how much 3 cakes would cost, we must first find the cost of each individual cake.
To do this, we must divide the cost of 8 cakes by 8 cakes.
4.00 ÷ 8 = 0.5
This means that each individual cake costs $0.50. Multiply this by 3 to find the cost of 3 cakes.
0.50 × 3 = 1.50
Therefore, 3 cakes would cost $1.50.
