For large sample confidence intervals about the mean you have:
xBar ± z * sx / sqrt(n)
where xBar is the sample mean z is the zscore for having α% of the data in the tails, i.e., P( |Z| > z) = α sx is the sample standard deviation n is the sample size
We need only to concern ourselves with the error term of the CI, In order to find the sample size needed for a confidence interval of a given size.
z * sx / sqrt(n) = width.
so the z-score for the confidence interval of .98 is the value of z such that 0.01 is in each tail of the distribution. z = 2.326348
The equation we need to solve is:
z * sx / sqrt(n) = width
n = (z * sx / width) ^ 2.
n = ( 2.326348 * 6 / 3 ) ^ 2
n = 21.64758
Since n must be integer valued we need to take the ceiling of this solution.
n = 22
B
1/4 = 8/3 * x
X = 8/12
X= 2/3
Answer:
x >_ 1
Step-by-step explanation:
Solving an inequality is a lot like solving an equation. Just pretend the inequality symbol is an equal sign!
(also i wont be using the _ or equal to symbol because I'm too lazy, so you'll get >_ or <_ for those, sorry)
8 + 4x >_ 12
-8 -8
4x >_ 4
/4 /4
x >_ 1
Answer: Brainliest plz?
.05 more seniors chose tropical paradise than juniors choosing a night in Paris
Step-by-step explanation:
55/100=.55
105/175=.60
.60-.55=.05
