Step-by-step explanation:
NO and PQ are congruent segments (have the same length), and both have the same midpoint M.
NO ≅ PQ, given.
NM ≅ ½ NO, definition of midpoint.
PM ≅ ½ PQ, definition of midpoint.
PM ≅ ½ NO, substitution.
PM ≅ NM, substitution.
Answer:
0.8 OR ![\frac{4}{5}](https://tex.z-dn.net/?f=%5Cfrac%7B4%7D%7B5%7D)
Step-by-step explanation:
The reciprocal of any number is the number that it multiplies by to equal 1.
The reciprocal can be found by simply converting the number into a fraction and then 'flipping' the fraction as any number multiplied by its reciprocal is 1.
E.g.
No. X/Y * Y/X (its reciprocal) = 1
![\frac{x}{y} *\frac{y}{x} =\frac{xy}{xy} =1](https://tex.z-dn.net/?f=%5Cfrac%7Bx%7D%7By%7D%20%2A%5Cfrac%7By%7D%7Bx%7D%20%3D%5Cfrac%7Bxy%7D%7Bxy%7D%20%3D1)
So, to find the reciprocal of 1.25,we should first convert 1.25 to a fraction.
1.25 = 125/100
![\frac{125/25}{100/25}=\frac{5}{4}](https://tex.z-dn.net/?f=%5Cfrac%7B125%2F25%7D%7B100%2F25%7D%3D%5Cfrac%7B5%7D%7B4%7D)
Now we just flip 5/4 to get our reciprocal:
= 0.8
Test: 0.8 * 1.25 = 1
The reciprocal of 1.25 (
) is 0.8 (
).
Hope this helped!
Answer:
-2; 1; 4; 7
Step-by-step explanation:
To solve for y, plug the x value in to the expression
y = 3(-1) + 1
y = -3 + 1
y = -2
When x = -1, y = -2
y = 3(0) + 1
y = 0 + 1
y = 1
When x = 0, y = 1
y = 3(1) + 1
y = 3 + 1
y = 4
When x = 1, y = 4
y = 3(2) + 1
y = 6 + 1
y = 7
When x = 2, y = 7
Answer:
Step-by-step explanation:
![x^{2} + 5x = 0](https://tex.z-dn.net/?f=x%5E%7B2%7D%20%2B%205x%20%3D%200)
On the left-hand side of the equation, both terms have a common factor of
, so we can pull that out:
![x(x + 5) = 0](https://tex.z-dn.net/?f=x%28x%20%2B%205%29%20%3D%200)
We can now create two equations from this to solve for
:
![x = 0](https://tex.z-dn.net/?f=x%20%3D%200)
![x + 5 = 0](https://tex.z-dn.net/?f=x%20%2B%205%20%3D%200)
The first equation doesn't need any further work, but the second equation can be reduced by substracting
from both sides to get
by itself on the left-hand side:
![x = -5](https://tex.z-dn.net/?f=x%20%3D%20-5)
Therefore, the two solutions to the problem are ![x = 0, -5](https://tex.z-dn.net/?f=x%20%3D%200%2C%20-5)