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Elena-2011 [213]
3 years ago
7

Three friends were born in consecutive years. The some of their birth years is 5982.find the year in which each person was born

Mathematics
1 answer:
posledela3 years ago
3 0
A+b+c=5982
find the average of the three friends 
5982/3=1994
add and subtract one to find the average 
1994+1=1995
1994-1=1993
add all the years together to check 
1993+1994+1995=5983
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2 years ago
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<em>Answer</em><em>:</em>

<h2><em>2</em><em>0</em><em> </em><em>years</em><em> </em><em>old</em><em>.</em></h2>

<em>Sol</em><em>ution</em><em>,</em>

<em>Let</em><em> </em><em>the</em><em> </em><em>age</em><em> </em><em>of</em><em> </em><em>sister</em><em> </em><em>be</em><em> </em><em>X</em>

<em>Let</em><em> </em><em>the</em><em> </em><em>age</em><em> </em><em>of</em><em> </em><em>boy</em><em> </em><em>be </em><em>2</em><em>x</em>

<em>Now</em><em>,</em>

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<em>3(x - 5) = 2x - 5 \\ or \: 3x - 15 = 2x - 5 \\ or \: 3x - 2x =  - 5 + 15 \\ x = 10</em>

<em>Again</em><em>,</em>

<em>Repla</em><em>cing</em><em> </em><em>value</em><em>,</em>

<em>age \: of \: boy = 2x \\  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  = 2 \times 10 \\  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  = 20</em>

<em>hope</em><em> </em><em>this</em><em> </em><em>helps</em><em>.</em><em>.</em>

<em>Good</em><em> </em><em>luck</em><em> on</em><em> your</em><em> assignment</em><em>.</em><em>.</em>

7 0
3 years ago
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