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3 years ago

Three friends were born in consecutive years. The some of their birth years is 5982.find the year in which each person was born

1 answer:

3 0

A+b+c=5982
find the average of the three friends
5982/3=1994
add and subtract one to find the average
1994+1=1995
1994-1=1993
add all the years together to check
1993+1994+1995=5983

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Step-by-step explanation:

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A quantity with an initial value of 600 decays exponentially at a rate of

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Answer:

The value of the quantity after 87 months will be of 599.64.

Step-by-step explanation:

A quantity with an initial value of 600 decays exponentially at a rate of 0.05% every 6 years.

This means that the quantity, after t periods of 6 years, is given by:

$Q(t) = 600(1 - 0.0005)^{t}$

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3 years ago