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ss7ja [257]
3 years ago
12

Combine like terms. 7a^2 - a^2 + 16 z^2 + z + 4z^3 + 4z^2 1/4(16 + 4p)

Mathematics
1 answer:
Ronch [10]3 years ago
5 0
1. -a^2+7x^2+16
2. 4z^3+5z^2+z
3. p+4
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The equation (1•2)^72 (72 20 minute periods in a day) would produce way more than 5 billion a day
5 0
3 years ago
Solve the equation.
Zina [86]

Answer:

x=5

Step-by-step explanation:

esa es la respuesta correcta

7 0
2 years ago
In a recent year, Washington State public school students taking a mathematics assessment test had a mean score of 276.1 and a s
Oksi-84 [34.3K]

Answer:

a) \mu_{\bar x} =\mu = 276.1

\sigma_{\bar x} =\frac{\sigma}{\sqrt{n}}=\frac{34.4}{\sqrt{64}}=4.3

b) From the central limit theorem we know that the distribution for the sample mean \bar X is given by:

\bar X \sim N(\mu=276.1, \frac{\sigma}{\sqrt{n}}=4.3)

c) P(\bar X \geq 285)=P(Z\geq \frac{285-276.1}{4.3}=2.070)

P(Z\geq2.070)=1-P(Z

Step-by-step explanation:

Let X the random variable the represent the scores for the test analyzed. We know that:

\mu=E(X) = 276.1 , \sigma=Sd(X) = 34.4

And we select a sample size of 64.

The central limit theorem states that "if we have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population with replacement, then the distribution of the sample means will be approximately normally distributed. This will hold true regardless of whether the source population is normal or skewed, provided the sample size is sufficiently large".

Part a

For this case the mean and standard error for the sample mean would be given by:

\mu_{\bar x} =\mu = 276.1

\sigma_{\bar x} =\frac{\sigma}{\sqrt{n}}=\frac{34.4}{\sqrt{64}}=4.3

Part b

From the central limit theorem we know that the distribution for the sample mean \bar X is given by:

\bar X \sim N(\mu=276.1, \frac{\sigma}{\sqrt{n}}=4.3)

Part c

For this case we want this probability:

P(\bar X \geq 285)

And we can use the z score defined as:

z=\frac{\bar x -\mu}{\sigma_{\bar x}}

And using this we got:

P(\bar X \geq 285)=P(Z\geq \frac{285-276.1}{4.3}=2.070)

And using a calculator, excel or the normal standard table we have that:

P(Z\geq2.070)=1-P(Z

8 0
3 years ago
Rounded to the nearest hundredth, what is the positive solution to the quadratic equation 0 = 2x2 + 3x – 8? Quadratic formula: x
Lynna [10]

ANSWER

1.39

EXPLANATION

The given quadratic equation is

0 = 2 {x}^{2}  + 3x - 8

This is the same as,

2 {x}^{2}  + 3x - 8 = 0

Comparing to

a {x}^{2}  + bx  + c = 0

We have

a=2, b=3,c=-8

Using the quadratic formula, the solution is given by:

x =  \frac{ - b \pm \:  \sqrt{ {b}^{2}  - 4ac} }{2a}

We substitute the values to get,

x =  \frac{ - 3\pm \:  \sqrt{ {3}^{2}  - 4(2)( - 8)} }{2(2)}

x =  \frac{ - 3\pm \:  \sqrt{ 73} }{4}

The positive root is

x =  \frac{ - 3 + \:  \sqrt{ 73} }{4} = 1.39

to the nearest hundredth.

4 0
3 years ago
Read 2 more answers
the temperature started at 89°f. if the temperature went up 6°f and then down 12°f, how many degrees above or below the high is
Sonja [21]
The answer is 6 degrees below the high. 
89+6=95
95-12=83
4 0
2 years ago
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