Answer: Maybe search it up?...I cant rlly see what the question says
Step-by-step explanation:
Answer:
d
Step-by-step explanation:
Solution by substitution method
y=7x+8
∴y-7x=8
and y=x+20
∴y-x=20
Suppose,
-7x+y=8→(1)
and -x+y=20→(2)
Taking equation (1), we have
-7x+y=8
⇒y=7x+8→(3)
Putting y=7x+8 in equation (2), we get
-x + 7x + 8 = 20
6x = 20-8
6x = 12
x= 12 / 6
x = 2
substitute for x in equation (3)
y = 7(x) + 8
y = 7(2) + 8
y = 22
Answer:
1 23/30
Step-by-step explanation:
you convet the mixed numbers into improper fractions then find the lowest common factor and combine :)
Answer:
Step-by-step explanation:
To find : Acceleration in first 15 min . Distance between two cities Average speed of journey
Solution:
Each horizontal block is 1/8 hr = 7.5 min
Each vertical block is 10 km/hr
Time Velocity km/hr
0 Min ( 0 hr) 0
15 Min (1/4 hr) 50
45 Min (3/4 hr) 50
60 MIn ( 1 hr) 100
90 Min ( 3/2 hr) 100
120 Min ( 2hr) 0
Acceleration in first 15 min (1/4 hr) = (50 - 0)/(1/4 - 0) = 50/(1/4)
= 200 km/h²
Distance between two cities
= (1/2)(0 + 50)(1/4 - 0) + 50 * (3/4 - 1/4) + (1/2)(50 + 100)(1 - 3/4) + 100 * (3/2 - 1) + (1/2)(100 + 0)(2 - 3/2)
= 25/4 + 25 + 75/4 + 50 + 25
= 125
Distance between two cities = 125 km
Average Speed of journey = 125/2 = 62.5 km/hr
Acceleration in first 15 min = 200 km/h²
Distance between two cities = 125 km
Average Speed of journey = 62.5 km/hr
Hope this helps..