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andrew-mc [135]
3 years ago
7

Please help me !! :))))

Mathematics
2 answers:
mario62 [17]3 years ago
7 0
I think a is your answer
vfiekz [6]3 years ago
7 0

Answer:

y = 1/2x - 3

Step-by-step explanation:

The -3 is where the line is positioned vertically on the graph on the Y axis.

The 1/2x is the slope:

Go up 1, over 2 to plot points on the line, starting from y = -3

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Last math question for today!!!!​
Alex777 [14]

Answer: Maybe search it up?...I cant rlly see what the question says

Step-by-step explanation:

3 0
3 years ago
Use the substitution methods to solve the system of equations. Choose the correct ordered pair. y=7x+8 y=x+20
krek1111 [17]

Answer:

d

Step-by-step explanation:

Solution by substitution method

y=7x+8

∴y-7x=8

and y=x+20

∴y-x=20

Suppose,

-7x+y=8→(1)

and -x+y=20→(2)

Taking equation (1), we have

-7x+y=8

⇒y=7x+8→(3)

Putting y=7x+8 in equation (2), we get

-x + 7x + 8 = 20

6x = 20-8

6x = 12

x= 12 / 6

x = 2

substitute for x in equation (3)

y = 7(x) + 8

y = 7(2) + 8

y = 22

4 0
3 years ago
The angle of elevation of the top of a tower from a point 100m away is 45 degrees. What is the height of the tower to the neares
vladimir2022 [97]

Answer:

SOHCAHTOA.

TOA=opposite/adjacent.

Tan45=100/h.

h tan45=100.

h×1=100.

h=100m

7 0
4 years ago
Read 2 more answers
2 3/5 - 5/6 as a mixed number
Vaselesa [24]

Answer:

1 23/30

Step-by-step explanation:

you convet the mixed numbers into improper fractions then find the lowest common factor and combine :)

6 0
3 years ago
The graph below describes the journey of a train between two cities
UkoKoshka [18]

Answer:

Step-by-step explanation:

To find : Acceleration in first 15 min . Distance between two cities  Average speed of journey

Solution:

Each horizontal block is 1/8 hr = 7.5 min

Each vertical block is 10 km/hr

Time                    Velocity  km/hr

0 Min  ( 0 hr)            0

15 Min (1/4 hr)           50

45 Min (3/4 hr)         50

60 MIn  ( 1 hr)            100

90 Min  ( 3/2 hr)        100

120 Min ( 2hr)            0

Acceleration in first 15 min  (1/4 hr)  =  (50 - 0)/(1/4 - 0)  = 50/(1/4)

= 200  km/h²

Distance between two cities

= (1/2)(0 + 50)(1/4 - 0)  + 50 * (3/4 - 1/4)  + (1/2)(50 + 100)(1 - 3/4)  + 100 * (3/2 - 1) + (1/2)(100 + 0)(2 - 3/2)

=  25/4  + 25 + 75/4   + 50 + 25

= 125

Distance between two cities = 125 km

Average Speed of journey = 125/2  = 62.5  km/hr

Acceleration in first 15 min = 200  km/h²

Distance between two cities = 125 km

Average Speed of journey =  62.5  km/hr

Hope this helps..

3 0
3 years ago
Read 2 more answers
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