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UkoKoshka [18]
3 years ago
9

In a c is ___ in b d is ___

Mathematics
1 answer:
ipn [44]3 years ago
7 0

Answer:

In equation A, c is 7

In equation B, d is 5

Step-by-step explanation:

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Could someone please help me with this problem and give me an explanation on how to solve it?
elena-s [515]

Answer:

B

Step-by-step explanation:

(a^3/2) / a

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2 years ago
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Write the 5th term in the expansion of (5x-y/2)^7
Nezavi [6.7K]

Answer:

65625/4(x^5)(y²)

Step-by-step explanation:

Using binomial expansion

Formula: (n k) (a^k)(b ^(n-k))

Where (n k) represents n combination of k (nCk)

From the question k = 5 (i.e. 5th term)

n = 7 (power of expression)

a = 5x

b = -y/2

....................

Solving nCk

n = 7

k = 5

nCk = 7C5

= 7!/(5!2!) ------ Expand Expression

=7 * 6 * 5! /(5! * 2*1)

= 7*6/2

= 21 ------

.........................

Solving (a^k) (b^(n-k))

a = 5x

b = -y/2

k = 5

n = 7

Substituting these values in the expression

(5x)^5 * (-y/2)^(7-5)

= (3125x^5) * (-y/2)²

= 3125x^5 * y²/4

= (3125x^5)(y²)/4

------------------------------------

Multiplying the two expression above

21 * (3125x^5)(y²)/4

= 65625/4(x^5)(y²)

5 0
3 years ago
Multiply and simplify. 3(x2 + 5)(x2 - 5)
Luba_88 [7]

Answer:

3 x^4 + -75

Step-by-step explanation:

Expand the following:

3 (x^2 + 5) (x^2 - 5)

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3 x^4 - 25

3 (x^4 - 25) = 3 x^4 + 3 (-25):

3 x^4 - 25×3

3 (-25) = -75:

Answer:  3 x^4 + -75

8 0
4 years ago
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