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2 years ago

What are risk factors of an autoimmune disease

Physics

1 answer:

ladessa [460]2 years ago

4 0

Explanation:

Your Sex. Overall, 78% of people affected by autoimmune disease are female (1). ...

Genetics. Certain disorders, such as lupus and multiple sclerosis, tend to run in families (3, 4). ...

Having an autoimmune disease. ...

Obesity. ...

Smoking and Exposure to Toxic Agents. ...
Certain Medications. ...

Infections.

You might be interested in

¿Qué velocidad inicial debe impartirse a una masa de 5kg para elevarla a una altura de 10m? ¿Cuál es la energía total en cualqui

Snowcat [4.5K]

Cada 100 cm es de 1 m por lo que tomar los kilos a su vez a cm, a continuación, a su vez a metros

6 0

3 years ago

Bill is farsighted and has a near point located 121 cm from his eyes. Anne is also farsighted, but her near point is 74.0 cm fro

Arada [10]

Answer:

Explanation:

The lens equation is

1 / f = 1 / di + 1 / do

Where

f is focal length

di is the image distance

do is the object distance

Both Annie and Billy use a glass whose near point is 25cm

Then, the object distance is

do = 25 - 2 = 23cm

The have the same object distance.

Let find the vocal length of bills eye

Given that,

Bill near point is 121cm and distance of the glass from the eye is 2cm

Then,

Image distance of bill is

di_B = -(121-2) = -119cm

object distance do = 23cm

Then,

1 / f_B = 1 / di_B + 1 / do

1 / f_B = -1 / 119 + 1 / 23

1 / f_B = -119^-1 + 23^-1

1 / f_B = 0.0351

Then, f_B = 28.51 cm

Also, let find Annie focal length

Given that,

Annie near point is 74 cm and distance of the glass from the eye is 2cm

Then,

Image distance of Annie is

di_A = -(74-2) = -72cm

object distance do = 23cm

Then,

1 / f_A = 1 / di_A + 1 / do

1 / f_A = -1 / 72 + 1 / 23

1 / f_A = -72^-1 + 23^-1

1 / f_A = 0.02959

Then, f_A = 33.8 cm

Distance of object from the lens when Annie uses Billy glass

Then,

1 / f_B = 1 / di_A + 1 / do

1 / 28.51 = -1 / 72 + 1 / do

28.51^-1 = -72^-1 + do^-1

do^-1 = 28.51^-1 + 72^-1

do^-1 = 0.048964

do = 20.42 cm

Then, the object location from the eye will be, the eye is 2cm from the glass. Then,

do_A = 20.42 + 2 = 22.42cm

do_A = 22.42 cm

Distance of object from the lens when Billy uses Annie glass

Then,

1 / f_A = 1 / di_B + 1 / do

1 / 33.8 = -1 / 119 + 1 / do

33.8^-1 = -119^-1 + do^-1

do^-1 = 33.8^-1 + 119^-1

do^-1 = 0.03799

do = 26.32 cm

Then, the object location from the eye will be, the eye is 2cm from the glass. Then,

do_B = 26.32 + 2 = 28.32 cm

do_B = 28.32 cm

7 0

3 years ago

A 10 kg box hangs from a rope. What is the tension in the rope (in Newtons) if the box is stationary

Archy [21]

Answer:

T = 98 N

Explanation:

The gravity of the earth is known to be 9.8 m/s²

Data:

m = 10 kg
g = 9.8 m/s²
T = ?

Use formula:

$\boxed{\bold{T=m*g}}$

Replace and solve:

$\boxed{\bold{T=10\ kg*9.8\frac{m}{s^{2}}}}$

$\boxed{\boxed{\bold{T=98\ N}}}$

The tension in the rope is <u>98 Newtons.</u>

Greetings.

5 0

3 years ago

The weight of the North American P-51 Mustang airplane is 10,100 lb and its wing platform area is 233 ft2 . Calculate the wing l

Natali5045456 [20]

Answer

given,

weight of airplane,W = 10,100 lb

Wing area,A = 233 ft²

now,

Wing Loading Calculation in English engineering

= $\dfrac{W}{A}$

= $\dfrac{10,100}{233}$

= 43.35 lb/ft²

Wing Loading in SI unit

= $43.35\times \dfrac{4.448\ N}{1\ lb}\times (\dfrac{1\ ft}{0.3048})^2$

= $2075.51\ N/m^2$

Wing loading in kgf/m²

= $\dfrac{2075.51}{9.81}$

= 211.57 kgf/m²

5 0

3 years ago

An object falls a distance h from rest. If it travels 0.560h in the last 1.00 s, find (a) the time and (b) the height of its fal

VashaNatasha [74]

Answer:

(a) t = 2.97s

(b) h = 43.3 m

Explanation:

Let t be the time it takes to fall a distance h, then t - 1 (s) is the time it takes to fall a distance of h - 0.56h = 0.44 h

For the ball to fall from rest a distance of h after time t

$h = gt^2/2$

Also for the ball to fall from rest a distance of 0.44h after time (t-1)

$0.44h = g(t-1)^2/2$

We can substitute the 1st equation into the 2nd one

$0.44gt^2/2 = g(t-1)^2/2$

and divide both sides by g/2

$0.44t^2 = (t-1)^2$

$0.44t^2 = t^2 - 2t + 1$

$0.56t^2 - 2t + 1 = 0$

$t= \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$

$t= \frac{2\pm \sqrt{(-2)^2 - 4*(0.56)*(1)}}{2*(0.56)}$

$t= \frac{2\pm1.33}{1.12}$

t = 2.97 or t = 0.6

Since t can only be > 1 s we will pick t = 2.97 s

(b) $h = gt^2/2 = 43.3 m$

6 0

3 years ago