N₂ / N₁ = 13.3
A transformer is a device that changes the voltage in the primary, causing a voltage to be induced in the secondary. The expression for this voltage ratio is
ΔV₂ = N₂ /N₁ ΔV₁
where N is the number of windings on each side and V2 and V1 are the voltages in the secondary and primary, respectively.
They state that the primary voltage in this instance is 9.0 V and the secondary voltage is 120 V.
ΔV₂ /ΔV₁ = N₂ / N₁
N₂ / N₁ = 120/9
N₂ / N₁ = 13.3
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A 9.0-V battery (with nonzero resistance) and switch are connected in series across the primary coil of a transformer. The secondary coil is connected to a light bulb that operates on 120 V. Determine the ratio of the secondary to primary turns needed for the bell's transformer. Determine the ratio of the secondary to primary turns needed for the bells transformer. Ns/Np=?
The kinetic energy of this block-spring when the block has a speed (v) is given by K.E = 1/2 × (M + m/3)v².
<h3>What is kinetic energy?</h3>
Kinetic energy can be defined as a form of energy that is possessed by a person due to its motion or change in speed (acceleration).
<h3>How to calculate kinetic energy?</h3>
Mathematically, kinetic energy can be calculated by using this formula:
K.E = 1/2 × mv²
Where:
- K.E represents the kinetic energy.
- v represents the speed or velocity.
Since the mass of a segment of this spring is dm = (m/l) dx, the kinetic energy for each of its segment would be given by:
dK = 1/2 × (dm)Vx²
This ultimately implies that, the kinetic energy of this block-spring when the block has a speed (v) is given by:
K.E = 1/2 × Mv² + 1/2 × ¹∫₀((x²v²/l²)m/ldx
K.E = 1/2 × (M + m/3)v².
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Answer:

Explanation:
Mass: M, Length: L.

The formula that gives center of mass is

In the case of a non-uniform mass density, this formula converts to

where the denominator is the total mass and the nominator is the mass times position of each point on the rod.
We have to integrate the mass density over the total rod in order to find the total mass. Likewise, we have to integrate the center of mass of each point (xσ(x)) over the total rod. And if we divide the integrated center of mass to the total mass, we find the center of mass of the rod:

Here x's are cancelled. Otherwise, the denominator would be zero.

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