All categories

2 years ago

How can you edit the light wave to increase the photosynthesis in the plant?

Physics

1 answer:

muminat2 years ago

7 0

Answer: C) Increase the amplitude of the wavelenghth to increase the intensity.

Explanation:

You might be interested in

Velocity: You leave on a 549-mi trip in order to attend a meeting that will start 10.8 h after you begin your trip. Along the wa

rewona [7]

Answer:

1.55 h

Explanation:

Let the time to spend over dinner be t.

Since I need to spend 10.8 h for the whole trip, then I have 10.8 - t hours left to drive.

Speed = distance/time

$v = \dfrac{d}{10.8-t}$

$d = v(10.8-t)$

The distance is 549 and maximum speed is 65 mi/h.

$549 = 65(10.8 - t)$

$10.8-t = 8.45$

$t = 10.8 - 8.45 = 1.55 \text{ h}$

5 0

2 years ago

A cheetah can accelerate from rest to a speed of 21.5 m/s in 6.75 s. What is its acceleration? m/s^2

grandymaker [24]

Answer:

Acceleration will be $a=3.185m/sec^2$

Explanation:

We have given final velocity v = 21.5 m/sec

Time t = 6.75 sec

As cheetah starts from rest so initial velocity u = 0 m/sec

From first equation of motion we know that v = u+at, here v is final velocity, u is initial velocity, a is acceleration and t is time

So $21.5=0+a\times 6.75$

$a=3.185m/sec^2$

6 0

3 years ago

Read 2 more answers

A housefly walking across a clean surface can accumulate a significant positive or negative charge. In one experiment, the large

nalin [4]

Answer:

1681714.28571 N/C

Yes it could exist

Explanation:

m = Mass of housefly = 12 m

q = Charge = 70 pC

g = Acceleration due to gravity = 9.81 m/s²

E = Electric field

When an object accumulates charge it means that it is gaining electrons making it negatively charged. This is the concept of static electricity.

Here, the electric force and the graviational force will balance each other

$F_e=W\\\Rightarrow qE=mg\\\Rightarrow E=\frac{mg}{q}\\\Rightarrow E=\frac{12\times 10^{-6}\times 9.81}{70\times 10^{-12}}\\\Rightarrow E=1681714.28571\ N/C$

1681714.28571 N/C of electric field would be required to levitate

The direction of the electric field would be upwards vertically.

In air the critical value of electric field is $3\times 10^6\ N/C$ which is more than the critical value of electric field in air. So, the electric field can exist.

5 0

2 years ago

A 1200 kg safe is 2.0 m above a heavy-duty spring when the rope holding the safe breaks. The safe hits the spring and compresses

makvit [3.9K]

<span>the spring constant is 200kN/m.
</span>
The work done on the spring by the the free falling safe is equal to the kinetic energy of the spring:

W1 = $\frac{1}{2}$ k $x^{2}$

The work done on the safe by gravity is the potential energy of the spring:

W2 = (mass of safe) x g x (height)
= 1000kg x 9.8 m/s^2 x (2 + 0.54)m
=1000kg x 9.8 m/s^2 x (2.54)m
= 24,892 N-m

W2 = W1 =24892 N-m
⇒ $\frac{1}{2}$ k $(0.5)^{2}$ = 24892 N-m

Therefore, k = $\frac{(24892)*2}{0.5*0.5}$ = 199136 kN/m.

The spring constant is 199,136 N/m ≈ 200 kN/m

7 0

3 years ago

Can someone help me?in the phy

blagie [28]

Answer:

so your answer is gonna be the first one which is A

5 0

3 years ago