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zvonat [6]
2 years ago
6

Three brothers divided a prize as follows. The oldest received %, the middle brother received ½, and the youngest received the r

emaining $120. What was the value, in dollars, of the prize?
Mathematics
1 answer:
GalinKa [24]2 years ago
5 0

Answer:

1200

Step-by-step explanation:

Ok since the oldest was given 2/5, the middle was given 1/2, and the youngest was given the rest, that means the fraction that the youngest was given has to make 2/5 + 1/2 + ? = 1. So we have the equation: \frac{2}{5} + \frac{1}{2} + x = 1. Now to add the fractions simply multiply 2/5 by 2/2 and multiply 1/2 by 5/5 To get the same denominator: \frac{4}{10} + \frac{5}{10}+x=\frac{9}{10}+x. This means that x is 1/10 , because in adding 1/10 you get the whole 10/10. So 120 is one tenth of the entire prize. This means to get the entire prize you simply multiply by 10. This gives you the equation 120 * 10 = 1200

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