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Komok [63]
2 years ago
5

in ____ structures, the computer repeats particular statements a certain number of times depending on some condition(s).

Computers and Technology
2 answers:
damaskus [11]2 years ago
4 0

In <u>looping</u> structures, the computer repeats particular statements for a certain number of times based on some condition(s).

<h3>What is a looping structure?</h3>

A looping structure can be defined as a type of function which instructs a computer to repeat specific statements for a certain number of times based on some condition(s).

This ultimately implies that, a computer repeats particular statements for a certain number of times based on some condition(s) in looping structures.

Read more on loop here: brainly.com/question/26130037

#SPJ11

Orlov [11]2 years ago
3 0
Looping structure is the answer to your question
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How do I type over Images (photo posted ​
Ber [7]
Oh a document, I do not believe that you have type on images, but if you were to type a text in a app called PicsArt and saved it and then put it onto the document over the picture it would work.
3 0
3 years ago
Read 2 more answers
Write the pseudocode for a program that will process attendance records of CA students. The students attend college five days a
Alenkasestr [34]

Using the knowledge of pseudocodes it will be possible to write a code that calculates the amount of hours worked and giving warnings about it.

<h3>Writing a pseudocode we have that:</h3>

<em>while </em>

<em>if number == 0</em>

<em>break</em>

<em>hours =0 </em>

<em>for i =1 to 5 </em>

<em>hours = hours + time_out[ i ] - time_in[ i ]</em>

<em> If hours >36 : </em>

<em>print ( "Name is " ,name)</em>

<em>print( "No of hours are ",hours)</em>

<em>print("Congratulaion! Your working hours are more than 36")</em>

<em>If hours <30 : #</em>

<em>print ( "Name is " ,name)</em>

<em>print( "No of hours are ",hours)</em>

<em>print("Warning !!!")</em>

<em>End loop</em>

See more about pseudocode at brainly.com/question/13208346

#SPJ1

3 0
2 years ago
An array is sorted (in ascending order) if each element of the array is less than or equal to the next element .
Aleks04 [339]

Answer:

// The program below checks if an array is sorted or not

// Program is written in C++ Programming Language.

// Comments are used for explanatory purpose

//Program Starts here

#include<iostream>

using namespace std;

//Function to check if the array is sorted starts here

int isSorted(int arr[], int count)

{

// Check if arrays has one or no elements

if (count == 1 || count == 0) {

return 1;

}

else

{

// Check first two elements

if(arr[0] >= arr[1])

{

return 0; // Not sorted

}

else

{ // Check other elements

int check = 0;

for(int I = 1; I<count; I++){

if (arr[I-1] > arr[I]) { // Equal number are allowed

check++; // Not sorted

}

}

}

if(check==0)

return isSorted(arr, count - 1); //Sorted

else

return 0; // Not sorted

}

// Main Method starts here

int main()

{

int count;

cin<<count;

int arr[count];

for(int I = 1; I<=count; I++)

{

cin>>arr[I-1];

}

int n = sizeof(arr) / sizeof(arr[0]);

if (isSorted(arr, n))

cout << "Array is sorted";

else

cout << "Array is not sorted";

}

8 0
3 years ago
Develop an sec (single error correction) code for a 16-bit data word. generate the code for the data word 0101000000111001. show
Kipish [7]

Answer:

code = 010100000001101000101

Explanation:

Steps:

The inequality yields 2^{k} - 1 > = M+K, where M = 16. Therefore,

The second step will be to arrange the data bits and check the bits. This will be as follows:

Bit position              number              Check bits            Data Bits

21                                   10101

20                                  10100

The bits are checked up to bit position 1

Thus, the code is 010100000001101000101

3 0
4 years ago
Read 2 more answers
1 #include 2 3 int max2(int x, int y) { 4 int result = y; 5 if (x &gt; y) { 6 result = x; 7 } 8 return result; 9 } 10 11 int max
Serhud [2]

Answer:

7

Explanation:

#include <stdio.h>

int max2(int x, int y) {

   int result = y;

   if (x > y) {

       result = x;

   }

   return result;

}

int max3(int x, int y, int z) {

   return max2(max2(x,y),z);

}

int main() {

   int a = 5, b = 7, c = 3;

   printf("%d",max3(a, b, c));

   printf("");

   return 0;

}

Hi, first of all, next time you post the question, it would be nice to copy and paste like above. This will help us to read the code easily. Thanks for your cooperation.

We start from the main function:

The variables are initialized → a = 5, b = 7, c = 3

max3 function is called with previous variables and the result is printed → printf("%d",max3(a, b, c));

We go to the max3 function:

It takes 3 integers as parameters and returns the result of → max2(max2(x,y),z)

Note that max2 function is called two times here (One call is in another call actually. That is why we need to first evaluate the inner one and use the result of that as first parameter for the outer call)

We go to the max2 function:

It takes 2 integers as parameters. If the first one is greater than the second one, it returns first one. Otherwise, it returns the second one.

First we deal with the inner call. max2(x,y) is max2(5,7) and the it returns 7.

Now, we need to take care the outer call max2(7, z) is max2(7, 3) and it returns 7 again.

Thus, the program prints 7.

6 0
3 years ago
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