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2 years ago

11

Can someone help me with this problem pleaseee

1 answer:

Firlakuza [10]2 years ago

4 0

Answer:

x-intercept: (-5, 0)

y-intercept: (0, -4)

Step-by-step explanation:

The x-intercept is as the name implies when the line intersects the x-axis (the horizontal axis) or when y is equal to 0. If you look at the graph it intersects the x-axis at (-5, 0). The y-intercept follows the same concept except it's when it intersects the y-intercept (vertical axis) or when x is equal to 0. If you look at the graph it, it intersects the y-axis at (-4, 0).

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Able, Ben and Cal each played a game able's score was six times ben's score, Cale score was a hird time of Able's score write do

Svetradugi [14.3K]

Answer:

Abel to Ben: 6

Abel to Carl: 3

Ben to Carl: 0.5

Step-by-step explanation:

First we formulate the problem in equations:

Abel = 6 * Ben

Cale = Abel / 3

If Cale's score is Abel's score over 3, so Abel's score is 3 times Cale's score.

If Abel's score is 6 times Ben's score, and 3 times Cale's score, then Cale's score is 2 times Ben's score (so Ben's score is 0.5 times Cale's score)

So, the ratio between all scores are the following:

Abel to Ben: 6

Abel to Carl: 3

Ben to Carl: 0.5

8 0

3 years ago

Read 2 more answers

The current population of a town is 10,000 and its growth in years can be represented by P(t) = 10,000(0.2)^t, where t is the ti

DiKsa [7]

Answer:

1) 20%

2) Choice a.

Step-by-step explanation:

$P(t)=10000(0.2)^t$

1) $P(0)$ is the population initially.

$P(1)$ is the population after a year.

$\frac{P(1)}{P(0)}$ represents the population increase factor.

So let's evaluate that fraction:

$\frac{P(1)}{P(0)}$

$\frac{10000(0.2)^1}{10000(0.2)^0}$

$\frac{0.2^1}{0.2^0}=\frac{0.2}{1}=0.2$

0.2=20%

2) Let's figure out the population growth in terms of months instead of years.

$P(t)=10000(0.2)^{t}$

We want t to represent months.

A full year is 12 months, in a full year we have that $P(1)=10000(0.2)^1=10000(0.2)=2000$

So we want a new P such that $P(12)=2000$ since 12 months equals a year.

Let's look at the functions given to see which gives us this:

a) $P(12)=10000(0.87449)^{12}=2000 \text{approximately}$

b) $P(12)=10000(0.87449)^{12(12)}=0 \text{ approximately}$

c) $P(12)=10000(0.87449)^{\frac{1}{12}}=9889 \text{approximately}$

d) $P(12)=10000(0.87449)^{12+12}=400 \text{approximately}$

So a is the function we want.

Also another way to look at this:

$P(t)=10000(.2)^t$ where $t$ is in years.

$P(t)=10000(.2^\frac{1}{12})^t$ where $t$ is in months.

And $.2^\frac{1}{12}=0.874485 \text{approximately}$

8 0

4 years ago

Winston plans to hire a moving company to help him

Rina8888 [55]

The maximum whole number of hours is 4 hours.

8 0

3 years ago

Consider the sequence: 12, 17, 22, ... , ... , .... What is the 405th term of this sequence?

Mice21 [21]

A_n= a₁+(n-1)d

a₁ first term

n terms

d distance between each value

a_n= 12+(405-1)(5)=2032

7 0

3 years ago

Read 2 more answers

Find the next two<br> numbers in the<br> sequence. What is<br> the rule?<br> 100, 25, 50, 12:5, 25,

Tema [17]

Answer:

6.25, 12.5

Step-by-step explanation:

The sequence goes divide by 4 then multiply by 2

6 0

3 years ago