First, we are going to find the radius of the yaw mark. To do that we are going to use the formula:

where

is the length of the chord

is the middle ordinate
We know from our problem that the tires leave a yaw mark with a 52 foot chord and a middle ornate of 6 feet, so

and

. Lets replace those values in our formula:




Next, to find the minimum speed, we are going to use the formula:

where

is <span>drag factor
</span>

is the radius
We know form our problem that the drag factor is 0.2, so

. We also know from our previous calculation that the radius is

, so

. Lets replace those values in our formula:



mph
We can conclude that Mrs. Beluga's minimum speed before she applied the brakes was
13.34 miles per hour.
1 way : 10d + 2d
another way: 5d + 5d + 2d

<u><em>Step-by-step explanation:</em></u>
- Since the triangle is right use the tangent ratio to solve for x

- Multiply both sides by
x ×
( divide both sides by
)
x = ≈ ( nearest tenth )
Answer:
he payed 34$ for the jacket
Step-by-step explanation:
Answer:
no its not fair..
Step-by-step explanation:
question: how do u have this problem and ur in college