Answer:
63/8 or 7 7/8
Step-by-step explanation:
-3/2 * -5 1/4
Change the mixed number into an improper fraction
-3/2 * -21/4
Multiply straight across the numerators and denominators
63/8
For the first question, yes, they are similar. Each of the corresponding sides has a ratio of 4:1 from the first polygon to the second, meaning they are similar. For the second question, the ratio is 1.6:1, and if we multiply the 10 on the bottom polygon by 1.6, we get 16, which is the answer.
For real though, I’m hoping you don’t get sent back there. I’m assuming you dislike it there, so good luck with your course. I’m here to help if you need it.
Lateral area = (perimeter)(height)
Perimeter = 3 + 3 + 3 = 9
Height = 6
9 * 6 = 54
Use a protractor to do the problem, but try finding th answer yourself
Answer:
t≈8.0927
Step-by-step explanation:
h(t) = -16t^2 + 128t +12
We want to find when h(t) is zero ( or when it hits the ground)
0 = -16t^2 + 128t +12
Completing the square
Subtract 12 from each side
-12 = -16t^2 + 128t
Divide each side by -16
-12/-16 = -16/-16t^2 + 128/-16t
3/4 = t^2 -8t
Take the coefficient of t and divide it by 8
-8/2 = -4
Then square it
(-4) ^2 = 16
Add 16 to each side
16+3/4 = t^2 -8t+16
64/4 + 3/4= (t-4)^2
67/4 = (t-4)^2
Take the square root of each side
±sqrt(67/4) =sqrt( (t-4)^2)
±1/2sqrt(67) = (t-4)
Add 4 to each side
4 ±1/2sqrt(67) = t
The approximate values for t are
t≈-0.092676
t≈8.0927
The first is before the rocket is launched so the only valid answer is the second one
