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1 year ago

Rule 1: Multiply by 2 then add 1 starting from 1.

Mathematics

1 answer:

Lyrx [107]1 year ago

8 0

The sequence 1 will be 3(n – 1) + 1. And the sequence 2 will be 9(n – 1) / 2 + 40.

<h3>What are sequence and series?</h3>

A sequence is a list of elements that have been ordered sequentially, such that members come either before or after.

Let n = natural number.

The sequence 1 will be multiplied by 2 then add 1 starting from 1. Then we have

⇒ 2(n – 1) + 1(n – 1) + 1

⇒ 3(n – 1) + 1

The sequence 1 will be divided by 2 then add 4 starting from 40. Then we have

⇒ (n – 1 / 2) + 4(n – 1) + 40

⇒ 9(n – 1) / 2 + 40

More about the sequence link is given below.

brainly.com/question/21961097

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Answer:

136

Step-by-step explanation:

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16x7=112

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6 0

2 years ago

If 3,000 bacteria, with a growth constant (k) of 2.8 per hour, are present at the beginning of an experiment, in how many hours

Ivenika [448]

Given:

Initial number of bacteria = 3000

With a growth constant (k) of 2.8 per hour.

To find:

The number of hours it will take to be 15,000 bacteria.

Solution:

Let P(t) be the number of bacteria after t number of hours.

The exponential growth model (continuously) is:

$P(t)=P_0e^{kt}$

Where, $P_0$ is the initial value, k is the growth constant and t is the number of years.

Putting $P(t)=15000,P_0=3000, k=2.8$ in the above formula, we get

$15000=3000e^{2.8t}$

$\dfrac{15000}{3000}=e^{2.8t}$

$5=e^{2.8t}$

Taking ln on both sides, we get

$\ln 5=\ln e^{2.8t}$

$1.609438=2.8t$ $[\because \ln e^x=x]$

$\dfrac{1.609438}{2.8}=t$

$0.574799=t$

$t\approx 0.575$

Therefore, the number of bacteria will be 15,000 after 0.575 hours.

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2 years ago

Fermium-253 has a half life of three days. A sample contains 400 g. How long will it take for the sample to decay to 100 g?

NemiM [27]

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2 years ago

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2 years ago

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