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3 years ago

Frances added two numbers and the resulting sum was an irrational number. If the first number was 54

Mathematics

1 answer:

faust18 [17]3 years ago

5 0

Answer:SOMEONE PLZZZ ANSWER THIS I NEED THE ANSWER TO

!!!!!!

Step-by-step explanation:

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Find the missing segment in the attached image

uranmaximum [27]

Answer:

25 units

Step-by-step explanation:

This problem can be solved by using concept of Basic proportionality theorem.

This theorem states that if there is line drawn parallel to any side of the triangle, and it intersect the other two sides, then

segment divided on those two sides are in equal proportion.

Let naem this triangle

the side containing 15 and 6 be AB, with A be point on segment having length 15 units

B be point on segment having length 6 units

c be point on segment having length ? units

DE line parallel to BC

Thus, if apply Basic proportionality theorem. in this then ratio formed will be

15/6 = ?/10

5/2 = ?/10

?= 5/2* 10 = 25

The length of missing segment is 25 units.

6 0

2 years ago

The measure of angle is 0 is 7pi/4. The measure of its reference angle is ___ °, and tan 0 is ____

ollegr [7]

Answer: pi/4 and -1

Step-by-step explanation:

7 0

1 year ago

On a map the scale is given as 2.5 inch: 4 miles. How many miles in real life is 5 inches on the map? *

liubo4ka [24]

Answer:

8 miles

Step-by-step explanation:

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2 years ago

Lisa drove 7,000 miles in 70 days. She drove the same number of miles each day.

inysia [295]

Answer: I'd assume its B 100 miles each day.

Step-by-step explanation:

Because 70 x 100 is 7,000 which is equal to the amount of miles stared in the question

5 0

3 years ago

Read 2 more answers

Assume a simple random sample of 10 BMIs with a standard deviation of 1.186 is selected from a normally distributed population o

kirza4 [7]

Answer:

a) H0: $\sigma = 1.34$

H1: $\sigma \neq 1.34$

b) $df = n-1= 10-1=9$

And the critical values with $\alpha/2=0.005$ on each tail are:

$\chi_{\alpha/2}= 1.735, \chi_{1-\alpha/2}= 23.589$

c) $t=(10-1) [\frac{1.186}{1.34}]^2 =7.05$

d) For this case since the critical value is not higher or lower than the critical values we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true deviation is not significantly different from 1.34

Step-by-step explanation:

Information provided

n = 10 sample size

s= 1.186 the sample deviation

$\sigma_o =1.34$ the value that we want to test

$p_v$ represent the p value for the test

t represent the statistic (chi square test)

$\alpha=0.01$ significance level

Part a

On this case we want to test if the true deviation is 1,34 or no, so the system of hypothesis are:

H0: $\sigma = 1.34$

H1: $\sigma \neq 1.34$

The statistic is given by:

$t=(n-1) [\frac{s}{\sigma_o}]^2$

Part b

The degrees of freedom are given by:

$df = n-1= 10-1=9$

And the critical values with $\alpha/2=0.005$ on each tail are:

$\chi_{\alpha/2}= 1.735, \chi_{1-\alpha/2}= 23.589$

Part c

Replacing the info we got:

$t=(10-1) [\frac{1.186}{1.34}]^2 =7.05$

Part d

For this case since the critical value is not higher or lower than the critical values we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true deviation is not significantly different from 1.34

5 0

2 years ago