

Multiply both numerator and denominator of
by the complex conjugate of the denominator, -2+9i.

Multiplication can be transformed into difference of squares using the rule:
.

By definition, i² is -1. Calculate the denominator.

Multiply complex numbers 5-3i and -2+9i in the same way as you multiply binomials.

Do the multiplications in
.

Combine the real and imaginary parts in -10+45i+6i+27.

Do the additions in
.

Divide 17+51i by 85 to get
.

The real part of
is
.

D=rt
So you're going to plug in the values listed: r= 9 1/2 and t=1 3/4
This will give you:
d=(9.5)(1.75)
Then you solve:
d=16.625
You should probably convert that decimal answer into a fraction since you're question gave it to you as a fraction.
Well obviously the two bottom graphs don't represent the two trucks meeting. So we can cross those out. Looking at the top two graphs we can tell that the line above is truck #2. In graph 1 it shows the second truck is slowing down which is wrong since that isn't told.
So the answer would be Graph #2
I hope this helps!
-Ayden
Answer:
x > 2/3
Step-by-step explanation:
-4(3x - 5) < 2(3x + 4)
Divide both sides by 2.
-2(3x - 5) < 3x + 4
Distribute on the left side.
-6x + 10 < 3x + 4
Subtract 3x from both sides.
-9x + 10 < 4
Subtract 10 from both sides.
-9x < - 6
Divide both sides by -9. Remember that when you divide both sides of an inequality by a negative number, the inequality sign changes direction.
x > (-6)/(-9)
x > 6/9
x > 2/3