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2 years ago

Here is the histogram of a data distribution. All class widths are 1.

Mathematics

1 answer:

Pachacha [2.7K]2 years ago

5 0

The correct answer is option B which is 3

Mean is defined as the ratio of the sum of the number of the data sets to the total number of the data.

Given data:-

4,3,2

The mean will be calculated as:-

Mean = (4 + 3 + 2) / 3

Mean = 9 / 3

Mean = 3

Therefore the correct answer is option B which is 3

To know more about mean follow

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Find the solution of the inequality -3n < 81

posledela

Answer:

n<-27

Step-by-step explanation:

you have to get n by itself, to do this divide -3 from both sides of the equations.

-3n/-3<81/-3

n<-27

the answer is n<-27

8 0

4 years ago

The side of a square is 3^2 inches. Using the area formula A = s^2, determine the area of thesquare.

elena55 [62]

Answer: it’s 81

Step-by-step explanation:

easy math I know it’s 81

3 0

3 years ago

What's n = 3 x 45 for 5th grade math please cause I'm not sure how this math goes

Drupady [299]

N=135. 45+45+45=135.

6 0

3 years ago

Please answer correctly <br> Option d is x=10 the picture was to big to include that option

Sladkaya [172]

Answer:

The answer is x = 10.

Step-by-step explanation:

Use the pythagorean theorem. A would be 6, B would be 8, and C would be solved by the product of that.

7 0

3 years ago

Lucy is using a one-sample t ‑test based on a simple random sample of size n = 22 to test the null hypothesis H 0 : μ = 16.000 c

slega [8]

Answer:

The value of test statistic is 1.338

Step-by-step explanation:

We are given the following in the question:

Population mean, μ = 16.000

Sample mean, $\bar{x}$ = 16.218

Sample size, n = 22

Alpha, α = 0.05

Sample standard deviation, s = 0.764

First, we design the null and the alternate hypothesis

$H_{0}: \mu = 16.000\text{ cm}\\H_A: \mu < 16.000\text{ cm}$

We use one-tailed t test to perform this hypothesis.

Formula:

$t_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{\sigma}{\sqrt{n}} }$

Putting all the values, we have

$t_{stat} = \displaystyle\frac{16.218 - 16.000}{\frac{0.764}{\sqrt{22}} } = 1.338$

Thus, the value of test statistic is 1.338

4 0

4 years ago