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Monica [59]
3 years ago
14

Someone help please! Determine the intercept of the line that passes through the following points ​

Mathematics
1 answer:
storchak [24]3 years ago
5 0

Answer:

x: (-5.0)

y: (0, -17.5)

Step-by-step explanation:

The x-intercept of the line is when y=0. In the table is the point (-5,0). This is the x-intercept.

To find the y-intercept, find when x=0. Write an equation for the table in y=mx + b. Find the slope between two points first.

m = \frac{y_2-y_1}{x_2-x_1} = \frac{7-0}{-7--5} =\frac{7}{-7+5}=-\frac{7}{2} = -3.5

The slope is -3.5. So the equation is

y - 7 = -3.5(x--7)

y - 7 = -3.5 (x+7)

y - 7 = -3.5x - 24.5

y = 3.5x - 17.5

Since it is in y=mx+b, b= -17.5 and this is the y-intercept.

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We can get two different equations from this:

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Which of the following is equivalent to 9^5/2.
Korvikt [17]

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a

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Which of the following statements about the volume of a sphere and the volume of a cone are true? Select two answers.
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B would be the answer to your question
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7x2 +11x-6/7x2 - 10x + 3
velikii [3]

Answer:

Final result :

 x + 2

 —————

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Step-by-step explanation:

Step-1 : Multiply the coefficient of the first term by the constant   7 • 3 = 21  

Step-2 : Find two factors of  21  whose sum equals the coefficient of the middle term, which is   -10 .

     -21    +    -1    =    -22  

     -7    +    -3    =    -10    That's it

Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above,  -7  and  -3  

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Step-4 : Add up the first 2 terms, pulling out like factors :

                   7x • (x-1)

             Add up the last 2 terms, pulling out common factors :

                   3 • (x-1)

Step-5 : Add up the four terms of step 4 :

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            Which is the desired factorization

Please mark brainliest and have a great day!

3 0
3 years ago
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A student S is suspected of cheating on exam, due to evidence E of cheating being present. Suppose that in the case of a cheatin
Kay [80]

Answer:

Step-by-step explanation:

Suppose we think of an alphabet X to be the Event of the evidence.

Also, if Y be the Event of cheating; &

Y' be the Event of not involved in cheating

From the given information:

P(\dfrac{X}{Y}) = 60\% = 0.6

P(\dfrac{X}{Y'}) = 0.01\% = 0.0001

P(Y) = 0.01

Thus, P(Y') \ will\ be = 1 - P(Y)

P(Y') = 1 - 0.01

P(Y') = 0.99

The probability of cheating & the evidence is present is = P(YX)

P(YX) = P(\dfrac{X}{Y}) \ P(Y)

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The probabilities of not involved in cheating & the evidence are present is:

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(b)

The required probability that the evidence is present is:

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(c)

The required probability that (S) cheat provided the evidence being present is:

Using Bayes Theorem

P(\dfrac{Y}{X}) = \dfrac{P(YX)}{P(Y)}

P(\dfrac{Y}{X}) = \dfrac{P(0.006)}{P(0.006099)}

P(\dfrac{Y}{X}) = 0.9838

5 0
3 years ago
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