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SVETLANKA909090 [29]
3 years ago
5

Write an equation for a circle with center at (6, –2) and diameter = 12.

Mathematics
1 answer:
SVEN [57.7K]3 years ago
4 0
(x+6)2+(y-10)2=36 , would be your equation.
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The equation of the known circle is x^2+y^2-4x-4y+4=0, and the two tangents passing through the point (4 , 2) and the point (4/5
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Answer:

Answer:

4x - 3y = 0

Step-by-step explanation:

The angle between the radius and the

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Rearrange 4y + 3x = 25 into this form

=

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4

X

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--

3

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Given a line with slope m then the slope

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т

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* = 4, thus

4.

3

3

4

y = 4 x+c+ is the partial equation

To find c substitute P(3, 4) into the partial

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4 = 4 +C+c= 4-4 = 0

=

y = { x + equation of radius in slope-

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Multiply through by 3

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=

4x - 3y = 0 + equation of radius in

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