All categories

3 years ago

Write an equation for a circle with center at (6, –2) and diameter = 12.

Mathematics

1 answer:

SVEN [57.7K]3 years ago

4 0

(x+6)2+(y-10)2=36 , would be your equation.

You might be interested in

How do I solve this?

aev [14]

I need more information in order to solve it

3 0

3 years ago

NEED HELP ASAP PLZZZZ

Law Incorporation [45]

Answer

highest he should make is 3599.55 and lowest is 3332.55 so a doesnt fit and b does

3 0

3 years ago

Read 2 more answers

What is Q=R+Rst; solve for s

oksano4ka [1.4K]

Step-by-step explanation:

q=r+rst

Rewrite the equation as

r+rst=q

Subtract r from both sides of the equation.

r st=q−r

Divide each term by rt

(r st )/rt=(q/rt)−(r/rt)

Cancel the common factor.

(

s=(q/rt)−1/t

6 0

3 years ago

Using the discriminant, how many real number solutions does this equation have? 3x^2 – 2 = 5x

Anvisha [2.4K]

The discriminant of this equation is 49. The solutions for this equation are x=2 and x=- $\frac{1}{3}$
I hope that helps.

7 0

3 years ago

Why is the value of q?

Rudiy27

Given:

QSR is a right triangle.

QT = 10

TR = 4

To find:

The value of q.

Solution:

Hypotenuse of QSR = QT + TR

= 10 + 4

= 14

Geometric mean of similar right triangle formula:

$\frac{\text { hypotenuse }}{\text { leg }}=\frac{\text { leg }}{\text { part }}$

$$\Rightarrow \frac{14}{q} =\frac{q}{4}$

Do cross multiplication.

$$\Rightarrow14\times 4 =q\times q$

$$\Rightarrow 56 =q^2$

Switch the sides.

$$\Rightarrow q^2 =56$

Taking square root on both sides.

$\Rightarrow q =2 \sqrt{14}$

The value of q is $2 \sqrt{14}$ .

8 0

3 years ago