Perimeter of a rectangle:
P=2I+2W=2(I+w)
But if the length and width of a rectangle are both double, then we would have:
Length=2I
width=2w
Therefore, its perimeter would be:
P=2(2I+2w)=4(I+w)
the old perimeter was P=2(I+w) and the new perimeter is P=4(I+w)=2[2(l+w)]
There the perimeter is twice as great.
Answer: C) the perimeter is twice as great.
Answer: Yes.
Step-by-step explanation:
You can graph it without being on zero or in an infinite decimal
Answer:
D. 65
Step-by-step explanation:
180-50=130
130 divided by 2 =65
hope this helps:)
Answer:
-2
Step-by-step explanation:
I think this was the question you were talking about.
Answer:
$9327
Step-by-step explanation:
Apparently, the cost function is supposed to be ...
C(x) = 0.4x^2 -112x +17167
This can be rewritten to vertex form as ...
C(x) = 0.4(x^2 -280) +17167
C(x) = 0.4(x -140)^2 +17167 -0.4(19600)
C(x) = 0.4(x -140)^2 +9327
The vertex of the cost function is ...
(x, C(x)) = (140, 9327)
The minimum unit cost is $9327.
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<em>Comment on the question</em>
You found the number of units that result in minimum cost (140 units), but you have to evaluate C(140) to find the minimum unit cost.