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fgiga [73]
2 years ago
6

Suppose that E and F are two events and that P(E)=0.3 and P(F|E)=0.5. What is P(E and F)?

Mathematics
1 answer:
Sergio [31]2 years ago
4 0

E and F are two events and that P(E)=0.3 and P(F|E)=0.5. Thus, P(E and F)=0.15


Bayes' theorem is transforming preceding probabilities into succeeding probabilities. It is based on the principle of conditional probability. Conditional probability is the possibility that an event will occur because it is dependent on another event.

P(F|E)=P(E and F)÷P(E)

It is given that P(E)=0.3,P(F|E)=0.5

Using Bayes' formula,

P(F|E)=P(E and F)÷P(E)

Rearranging the formula,

⇒P(E and F)=P(F|E)×P(E)

Substituting the given values in the formula, we get

⇒P(E and F)=0.5×0.3

⇒P(E and F)=0.15

∴The correct answer is 0.15.

If, E and F are two events and that P(E)=0.3 and P(F|E)=0.5. Thus, P(E and F)=0.15.

Learn more about Bayes' theorem on

brainly.com/question/17010130

#SPJ1

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60 degrees.

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14. Given: 5x + 4y = 24, x + 7y= 11; Prove: y= 1<br> Statements<br> reasons
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Step-by-step explanation:

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—————————

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3 years ago
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Step-by-step explanation: need more

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3 years ago
PLEASE HELP!!!
kramer

The arc is defined by an angle of 1.05 radians, and a length of 1.05 units.

<h3 /><h3>How to get the angle in radians?</h3>

Remember the relation:

180° = 3.14 radians.

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