Ask question

Ask question

All categories

2 years ago

8

Jane has 5 nickels. john has 3 dimes. jane says she has a greater amount of money. with the information given, is she correct?

1 answer:

joja [24]2 years ago

7 0

No Jane is not correct she has 25 cents where john has 30 cents

You might be interested in

Y= 5(x − 2)(x + 1)<br> Standard form?

Yanka [14]

Answer:

pp

Step-by-step explanation:

8 0

2 years ago

Read 2 more answers

Adrian knows that the quotient of 0.75 divided by 0.8 is less than 1. He knows that the quotient of 0.8 divided by 0.75 is great

MrRa [10]

Hey There!

Adrian knows this because whenever you divide something less than the number you are dividing, in this case, then the quotient will be less than one. If you divide something that is greater than the number you are dividing, than in this case, the answer will be greater than one.

Have A Brainly Day!

7 0

3 years ago

What is (x − 3)(x − 5) = 35

JulijaS [17]

Answer:

x=10 x=-2

Step-by-step explanation:

(x − 3)(x − 5) = 35

FOIL

x^2 -5x-3x+15 = 35

Combine like terms

x^2 -8x+15 = 35

Subtract 35 from each side

x^2 -8x+15-35 = 35-35

x^2 -8x-20 =0

Factor

What 2 numbers multiply to -20 and add to -8

-10*2 = -20

-10 +2 = -8

(x-10)(x+2) =0

Using the zero product property

x-10 =0 x+2 = 0

x=10 x=-2

6 0

3 years ago

Q6. (15 points) IQ examination scores of 500 members of a club are normally distributed with mean of 165 and SD of 15.

melamori03 [73]

Answer:

a) 0.8413

b) 421

c) $P_{95} = 189.675$

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 165

Standard Deviation, σ = 15

We are given that the distribution of IQ examination scores is a bell shaped distribution that is a normal distribution.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

a) P(IQ scores at most 180)

P(x < 180)

$P( x < 180) = P( z < \displaystyle\frac{180 - 165}{15}) = P(z < 1)$

Calculation the value from standard normal z table, we have,

$P(x < 180) = 0.8413 = 84.13\%$

b) Number of the members of the club have IQ scores at most 180

n = 500

$\text{Members} = n\times \text{P(IQ scores at most 180)}\\= 500\times 0.8413\\=420.65 \approc 421$

c) P(X< x) = 0.95

We have to find the value of x such that the probability is 0.95

$P( X < x) = P( z < \displaystyle\frac{x - 165}{15})=0.95$

Calculation the value from standard normal z table, we have,

$P(z < 1.645) = 0.95$

$\displaystyle\frac{x - 165}{15} = 1.645\\\\x = 189.675$

$P_{95} = 189.675$

8 0

3 years ago

Find three ratios equivalent to the given ratio 8/10 5/2

valkas [14]

For 8/10:
16/20
24/30
64/80

for 5/2:
10/4
20/8
100/40

hope this helps

7 0

3 years ago