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2 years ago

Jane has 5 nickels. john has 3 dimes. jane says she has a greater amount of money. with the information given, is she correct?

Mathematics

1 answer:

joja [24]2 years ago

7 0

No Jane is not correct she has 25 cents where john has 30 cents

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Mixed numbers from 0-2 with intervals of 1/3

prisoha [69]

0, 1/3, 2/3, 1, 1 1/3, 1 2/3, 2

5 0

2 years ago

HELP MEE PLEASE! PLEASE DONT MESS AROUND!

Luden [163]

Answer:

its rotation

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3 years ago

Use the Taylor series you just found for sinc(x) to find the Taylor series for f(x) = (integral from 0 to x) of sinc(t)dt based

Marina CMI [18]

In this question (brainly.com/question/12792658) I derived the Taylor series for $\mathrm{sinc}\,x$ about $x=0$ :

$\mathrm{sinc}\,x=\displaystyle\sum_{n=0}^\infty\frac{(-1)^nx^{2n}}{(2n+1)!}$

Then the Taylor series for

$f(x)=\displaystyle\int_0^x\mathrm{sinc}\,t\,\mathrm dt$

is obtained by integrating the series above:

$f(x)=\displaystyle\int\sum_{n=0}^\infty\frac{(-1)^nx^{2n}}{(2n+1)!}\,\mathrm dx=C+\sum_{n=0}^\infty\frac{(-1)^nx^{2n+1}}{(2n+1)^2(2n)!}$

We have $f(0)=0$ , so $C=0$ and so

$f(x)=\displaystyle\sum_{n=0}^\infty\frac{(-1)^nx^{2n+1}}{(2n+1)^2(2n)!}$

which converges by the ratio test if the following limit is less than 1:

$\displaystyle\lim_{n\to\infty}\left|\frac{\frac{(-1)^{n+1}x^{2n+3}}{(2n+3)^2(2n+2)!}}{\frac{(-1)^nx^{2n+1}}{(2n+1)^2(2n)!}}\right|=|x^2|\lim_{n\to\infty}\frac{(2n+1)^2(2n)!}{(2n+3)^2(2n+2)!}$

Like in the linked problem, the limit is 0 so the series for $f(x)$ converges everywhere.

7 0

3 years ago

Why is -7 an integer but not a natural number?

MrMuchimi

Answer:

Natural Numbers are basically "counting numbers". If I ask you to start counting, you'll start at 1, then 2, then 3, and so on. It doesn't include 0 or any negative numbers because you wouldn't start from -10 when asked to count.

<h3>brainliest is appreciated :)</h3>

3 0

2 years ago

Read 2 more answers

You can do both problems if want

Agata [3.3K]

A= π r2 and v=3.14d

---Volume(v=3.14d):

3.14(15) equals 47.1

47.1 rounds to 47

nearest hundreth would be 0 that rounds to .1 or .10,which rounds to 47
v=47

---Area(π r2)

3.14(7.5)^2 is 3.14(56.25)
176.625

176.625 rounded to the nearest hundreth is 176.630.

Answer:

The area of a circle with the diameter of 15 is 176.630.

4 0

3 years ago