13. 440
14. 15
15. grade 6...not 100% sure on this...might be both grades
Answer:
When they are equal, y=y, so we can say:
x^2+5x-2=x+1 subtract x from both side
x^2+4x-2=1 add 2 to both sides
x^2+4x=3, now add half the linear coefficient squared, (4/2)^2=4
x^2+4x+4=3+4 now the left side is a perfect square
(x+2)^2=7 now take the square root of both sides
x+2=±√7 subtract 2 from both sides
x=-2±√7
x=-2+√7 and -2-√7
y=x+1 the two points where these equations are equal are:
(-2-√7, -1-√7) and (-2+√7, -1+√7)
or approximately:
(-4.65, -3.65) and (0.65, 1.65)
Step-by-step explanation:
The domain is read from the horizontal axis.
{-2; -1; 0; 1; 2}
Answer: D)
Answer:
Step-by-step explanation:
The square is in the circle, so the diameter is the diagonal line of the square. This divides the square into two right triangles.
Two sides of the right triangle equal 8. This qualifies it as a special right triangle. This triangle has two sides that = x (in this case 8) and the hypotenuse is .
Substitute 8 in for x.
is the diameter, so we divide in half to get the radius =