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2 years ago

Given the speeds of each runner below, determine who runs the fastest.

Mathematics

2 answers:

malfutka [58]2 years ago

7 0

Answer:

brooke 14 feet in one sec

Step-by-step explanation:

stephanie 12 feet 1 sec

liz 8 feet in 1 sec

will approx 6 feet in 1 sec

brooke 14 feet in one sec

alexandr402 [8]2 years ago

5 0

Answer:

Brooke

Step-by-step explanation:

We can solve this by figuring out how far each person runs a second

Stephanie runs 12 feet a second so nothing needs to be done here

Liz runs 306 feet in 38 seconds. To solve for the distance ran in 1 second we can divide (306/38)= around 8 feet

Will runes 1 mile in 491 seconds. A quick search will tell use that 1 mile is equal to 5280 feet and 5280/491 = 10.75

Brooke runs 851 feet in 1 minute or 60 seconds. 851/60 =14.18

Brooke obviously runs the furthest in one second and therefore she's the fastest runner

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Write each expression as an algebraic (nontrigonometric) expression in u, u > 0.

max2010maxim [7]

Answer:

$\displaystyle \sin\left(2\sec^{-1}\left(\frac{u}{10}\right)\right)=\frac{20\sqrt{u^2-100}}{u^2}\text{ where } u>0$

Step-by-step explanation:

We want to write the trignometric expression:

$\displaystyle \sin\left(2\sec^{-1}\left(\frac{u}{10}\right)\right)\text{ where } u>0$

As an algebraic equation.

First, we can focus on the inner expression. Let θ equal the expression:

$\displaystyle \theta=\sec^{-1}\left(\frac{u}{10}\right)$

Take the secant of both sides:

$\displaystyle \sec(\theta)=\frac{u}{10}$

Since secant is the ratio of the hypotenuse side to the adjacent side, this means that the opposite side is:

$\displaystyle o=\sqrt{u^2-10^2}=\sqrt{u^2-100}$

By substitutition:

$\displaystyle= \sin(2\theta)$

Using an double-angle identity:

$=2\sin(\theta)\cos(\theta)$

We know that the opposite side is √(u² -100), the adjacent side is 10, and the hypotenuse is u. Therefore:

$\displaystyle =2\left(\frac{\sqrt{u^2-100}}{u}\right)\left(\frac{10}{u}\right)$

Simplify. Therefore:

$\displaystyle \sin\left(2\sec^{-1}\left(\frac{u}{10}\right)\right)=\frac{20\sqrt{u^2-100}}{u^2}\text{ where } u>0$

4 0

3 years ago

You are facing South. You make an about face, then turn 90 degrees right. What direction are you facing?

Roman55 [17]

Answer:

west

Step-by-step explanation:

4 0

3 years ago

Cameron went into a grocery store and bought 4 apples abd 7 mangoes, costing a total of $17.75. Gavin went into the same grocery

rusak2 [61]

Answer:

7.00

Step-by-step explanation:

you subtract the 2 totals.

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3 years ago

Admission to the Hersheypark Theme Park in Hershey, Pennsylvania is $52.95 for an

shepuryov [24]

Answer:

42.95x + 21.95y

Step-by-step explanation:

5 0

3 years ago

1. The coordinates of the vertices of parallelogram RMBS are R(–4, 5), M(1, 4), B(2, –1), and S(–3, 0). Using the diagonals, pro

Whitepunk [10]

First, plot the points. Point R would be somewhere in the second Quadrant, point M would be in the first quadrant 1, point B would be in the fourth quadrant, and point S would be on the negative y-axis. A property of rhombi is that their diagonals are perpendicular. One would need to calculate the slopes of the diagonals and determine whether or not they are perpendicular. Lines are perpendicular if and only if their slopes are opposite reciprocals. Example: 2 and -0.5
Formulas needed:
Slope formula:
$\frac{ y_{2}- y_{1} }{ x_{2} - x_{1} }$

The figure would look kinda like this:
R
M

S
B
Diagonals are segment RB and segment SM
So, your slope equations would look like this:
$\frac{-1-5}{2-(-4)}$
and
$\frac{4-(-3)}{1-0}$
Slope of RB= -1
Slope of SM=7
Not a rhombus, slopes aren't perpendicular. But this figure may very well be a parallelogram

7 0

3 years ago