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Fudgin [204]
3 years ago
15

Given the speeds of each runner below, determine who runs the fastest.

Mathematics
2 answers:
malfutka [58]3 years ago
7 0

Answer:

brooke 14 feet in one sec

Step-by-step explanation:

stephanie 12 feet 1 sec

liz 8 feet in 1 sec

will approx 6 feet in 1 sec

brooke 14 feet in one sec

alexandr402 [8]3 years ago
5 0

Answer:

Brooke

Step-by-step explanation:

We can solve this by figuring out how far each person runs a second

Stephanie runs 12 feet a second so nothing needs to be done here

Liz runs 306 feet in 38 seconds. To solve for the distance ran in 1 second we can divide (306/38)= around 8 feet

Will runes 1 mile in 491 seconds. A quick search will tell use that 1 mile is equal to 5280 feet and 5280/491 = 10.75

Brooke runs 851 feet in 1 minute or 60 seconds. 851/60 =14.18

Brooke obviously runs the furthest in one second and therefore she's the fastest runner

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Put this on order from greatest to least pls​
Nostrana [21]

Answer:

0.497 < 1/2 < 0.55 < 3/5 < 6/7

Step-by-step explanation:

Order from Least to Greatest

1: Using the given inputs

2: Rewriting these inputs as decimals

3: Sorting this table by decimal values in order from least to greatest

4: Therefore, the sorted inputs in order from least to greatest is

Answer: 0.497 < 1/2 < 0.55 < 3/5 < 6/7

Hope this helps.

3 0
3 years ago
If two 10-sided number cubes are rolled, which of the following sample space tools should be used to best show all of the outcom
yanalaym [24]

Answer:

A table

Step-by-step explanation:

you can start with one and have all the numbers that can land with one than two then three etc.

123

1 1 1

222

333

444

555

666

.........

8 0
3 years ago
How do you turn 2 3/8 into a improper fractions
sasho [114]
19/8 is the improper fraction of 2 3/8.
4 0
3 years ago
Read 2 more answers
HELP ASAP- I would give 40 points just for these 3 answers
Slav-nsk [51]
5) The relation between intensity and current appears linear for intensity of 300 or more (current = intensity/10). For intensity of 150, current is less than that linear relation would predict. This seems to support the notion that current will go to zero for zero intensity. Current might even be negative for zero intensity since the line through the points (300, 30) and (150, 10) will have a negative intercept (-10) when current is zero.

Usually, we expect no output from a power-translating device when there is no input, so we expect current = 0 when intensity = 0.


6) We have no reason to believe the linear relation will not continue to hold for values of intensity near those already shown. We expect the current to be 100 for in intensity of 1000.


8) Apparently, times were only measured for 1, 3, 6, 8, and 12 laps. The author of the graph did not want to extrapolate beyond the data collected--a reasonable choice.
7 0
3 years ago
The architects side view drawing of a saltbox-style house shows a post that supports the roof ridge. The support post is 10 ft t
pochemuha
These calculations are based on the drawing of the file enclosed.

There are three right triangles.

From the big right triangle:

a^2 + b^2 = 25^2

From the small right triangle on the left side:


(25-x)^2 + 10^2 = a^2

From the small right triangle on the right side

x^2 +10^2 = b^2

=> (25-x)^2 + 10^2 + x^2 + 10^2 = a^2 + b^2

=> (25-x)^2 + 10^2 + x^2 + 10^2 = 25^2

=> 25^2 - 50x + x^2 + 10^2 + 10^2 = 25^2

=> x^2 -50x + 100 =0

Use the quadratic formular to find the roots:

x = 2.1 and x = 47.9

Distance from back: 25 - 2.1 = 22.9 ft

Answer: 22.9 ft
8 0
3 years ago
Read 2 more answers
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