A^2 + 31 = 155 - I squared each of b and c for those numbers
a^2 = 155 - 31
a^2 = 124
a = 4 * sqrt(31)
A number less than three would be 1 or 2.
2/7 is the probability that the first satellite sends a weak signal. That leaves 6, one of which sends a weak signal. So the probability that the second also sends a weak signal is 1/6. Combine these and we get 2/7×1/6=1/21.
Hi!
Use The Percentage Formula To Solve:
385 ÷ 550 * 100 = 70
Mark pays 70% of the original price.
