Simplify the expression by combining like terms. <br> 2x + 4y + 6 + 2y

A confidence interval (CI) is desired for the true average stray-load loss u (watts) for a certain type of induction motor when

Genrish500 [490]

Answer:

A) CI = (57.12 , 59.48)

B) CI = (57.71 , 58.89)

C) CI = (57.53 , 59.07)

D) n = 239.63

Step-by-step explanation:

a)

given data:

mean, $\bar X = 58.3$

standard deviation, σ = 3

sample size, n = 25Given CI level is 95%, hence α = 1 - 0.95 = 0.05

α/2 = 0.05/2 = 0.025,

Zc = Z(α/2) = 1.96

$ME = Zc * σ \sqrt{n}$

$ME = 1.96 * 3 \sqrt{25}$

ME = 1.18

$CI = (\bar X - Zc * s\sqrt{n} , \barX + Zc * s\sqrt{n})$

$CI = (58.3 - 1.96 * 3\sqrt{25} , 58.3 + 1.96 * 3\sqrt{25})$

CI = (57.12 , 59.48)

b)

Given data:

mean, $\bar X = 58.3$

standard deviation, σ = 3

sample size, n = 100

Given CI level is 95%, hence α = 1 - 0.95 = 0.05

α/2 = 0.05/2 = 0.025, Zc = Z(α/2) = 1.96

$ME = zc * σ \sqrt{n}$

$ME = 1.96 * 3\sqrt{100}$

ME = 0.59

$CI = (\bar X - Zc * s\sqrt{n} , \barX + Zc * s\sqrt{n})$

$CI = (58.3 - 1.96 * 3\sqrt{100} , 58.3 + 1.96 * 3\sqrt{100})$

CI = (57.71 , 58.89)

c)

sample mean, $\bar X = 58.3$

sample standard deviation, σ = 3

sample size, n = 100

Given CI level is 99%, hence α = 1 - 0.99 = 0.01

α/2 = 0.01/2 = 0.005, Zc = Z(α/2) = 2.58

$ME = Zc * σ \sqrt{n}$

$ME = 2.58 * 3\sqrt{100}$

ME = 0.77

$CI = (\bar X - Zc * s\sqrt{n} , \barX + Zc * s\sqrt{n})$

$CI = (58.3 - 2.58 * 3\sqrt{100} , 58.3 + 2.58 * 3/\sqrt{100}$

CI = (57.53 , 59.07)

D)

Given data:

Significance Level, α = 0.01,

Margin or Error, E = 0.5,

σ = 3

The critical value for α = 0.01 is 2.58.

for calculating population mean we used

$n \geq (zc *σ/E)^2$

$n = (2.58 * 3/0.5)^2$

n = 239.63

7 0

3 years ago

please help. i’ve been stuck on this question the past 10 minutes i’ve tried multiple times and still don’t get it. i need help

Softa [21]

Answer:

To solve the equation, you have to to isolate the variable. So, first you subtract both sides by 7.

x +7 - 7 = -2 - 7

When you simplify further,

x = -9.

Hope this helps! :)

3 0

2 years ago

One counting number is 4 times great as a counting number.The product of the two number is 36.What is the sum of the two number

VARVARA [1.3K]

Answer:

The sum of the two numbers is 15

Step-by-step explanation:

Let the counting numbers be x and y.

Then we can write the following equations

x=4y.......1 (one is four times greater )

x(y)=36.....2 (the product of the two)

Putting equation 1 into equation 2, we get

4y(y)=36

${4y}^{2} = 36$

Dividing through by 4,we get

${y}^{2} = \frac{36}{4}$

${y}^{2} = 9$

Taking square root of both side, we obtain

y=3

Putting the value of y into equation , we get

x=4(3)=12

Hence the numbers are 3 and 12

Therefore the sum of the two numbers is 3+12=15

3 0

3 years ago

Show an equation to find out how many milliliters are in 3.4 L

Allisa [31]

Answer:

3,400 ml

Step-by-step explanation:

Conversion factor: 1000

2) mL = L * 1000

3) mL = 3.4 * 1000

4) mL = 3400

3 0

3 years ago

Write 2^8 * 8^2 * 4^-4 in the form 2^n

Eva8 [605]

The given expression 2^8 * 8^2 * 4^-4 can be written in the exponential form 2^n as 2^6.

<h3>What are exponential forms?</h3>

The exponential form is a more convenient way to write repetitive multiplication of the same integer by using the base and its exponents.

<u>For example:</u>

If we have a*a*a*a, it can be written in exponential form as:

=a^4

where

a is the base, and
4 is the power.

The power in this format reflects the number of times we multiply the base by itself. The exponent is also known as the index or power.

From the information given:

We can write 2^8 * 8^2 * 4^-4 in form of 2^n as follows:

$\mathbf{= 2^8\times (2^3)^2 \times (2^2)^{-4} }$

$\mathbf{= 2^8\times (2^6) \times (2^{-8}) }$

$\mathbf{= 2^{8+6+(-8)}}$

$\mathbf{= 2^{6}}$

Therefore, we can conclude that by using the exponential form, the given expression 2^8 * 8^2 * 4^-4 in the form 2^n is 2^6.

Learn more about exponential forms here:

brainly.com/question/8844911

#SPJ1

4 0

2 years ago

Simplify the expression by combining like terms. 2x + 4y + 6 + 2y - 5 + 3x ￼

Simplify the expression by combining like terms. 2x + 4y + 6 + 2y - 5 + 3x