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2 years ago

8

For the following distribution: x p(x) 0 01.30 1 0.346 2 0.346 3 0.154 4 0.026 what is the mean of the distribution?

1 answer:

bogdanovich [222]2 years ago

5 0

The mean of the distribution given is 0.569.

Given some distribution like under:

x p(x)

0 0.650

1 0.216

2 0.087

3 0.026

4 0.014

5 0.009

We have to find the mean of the distribution.

Mean is the sum of numbers divided by the numbers which are taken into consideration. It is also known as average.

Mean=sum/n

To find the mean of distribution we have to find sum of x*p(x)

∑xp(x)=0*0.650+1*0.216+2*0.0087+3*0.026+4*0.014+5*0.009

=0+0.216+0.174+0.078+0.056+0.045

=0.569

Hence the mean of the distribution given in the question is 0.569.

Learn more about mean at brainly.com/question/1136789

#SPJ4

Distribution in the given question is wrong and the right question is as the right distribution is as under:

x p(x)

0 0.650

1 0.216

2 0.087

3 0.026

4 0.014

5 0.009

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<h2>[1]</h2>

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<h2>[2]</h2>

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