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2 years ago

Find the similarity ratio and the ratio of the perimeters of two regular octagons with areas of 18 in2 and 50 in2.

Mathematics

2 answers:

CaHeK987 [17]2 years ago

7 0

Answer:

Your answer would be

3:5; 3:5

Step-by-step explanation:

Brums [2.3K]2 years ago

4 0

By definition we have that the area of a regular octagon is:
A = 4.83L ^ 2
Where, L is the length of the octagon side.
the similarity ratio = the area ratio.
We have then:
similarity ratio = (50) / (18) = 25/9.
the ratio of the perimeters
A1 = 4.83L1 ^ 2
L1 ^ 2 = A1 / 4.83
L2 ^ 2 = A2 / 4.83
L1 ^ 2 / L2 ^ 2 = A1 / A2 = 25/9
L1 / L2 = 5/3
The perimeter is:
P1 = 8L1
P2 = 8L2
P1 / P2 = 8L1 / 8L2 = L1 / L2 = 5/3
answer:
similarity ratio:
25: 9
the ratio of the perimeters:
5: 3

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babunello [35]

Answer:

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Step-by-step explanation:

When we have a population model for two species as we have here, the differential equations looks like this:

$\frac{dx}{dt}=a*x+b\frac{x^{2}}{N}+c*xy$

$\frac{dy}{dt}=d*x+e\frac{y^{2}}{M}+f*xy)$

Here:

a and d are the the growth rates parameter for x and y respectively

N and M are the carrying capacities for x and y respectively

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So in our case we have:

$\frac{dx}{dt}=2*x+\frac{x^{2}}{16}+2*xy$

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I hope it helps you!

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